1. -6 ≤ x < -1 . . . . conjunction
2. x ≤ 6 . . or . . 10 ≤ x . . . . disjunction
3. 7 ≤ x < 12 . . . . conjunction
4. x < -9 . . or . . -3 ≤ x . . . . disjunction
5. 2 ≤ x ≤ 5 . . . . conjunction
6. x ≤ 54 . . or . . 66 ≤ x . . . . disjunction
7. 39 < x ≤ 43 . . . . conjunction
_____
Your problem statement provided no letters.
Answer:
i) superset (A)
ii) 0.577 (A)
Step-by-step explanation:
i) A subset is a set which has all its elements contained in another set.
For two sets A and B, if each element of set A is an element of set B, then A is a subset of B.
A superset is a set that houses another set. So if set A is a subset of set B, then B is a superset of A.
Proper subset
For a set (A) to be a proper subset of another (B) every element of A would be in B but there exists at least one element in B that is not in A.
An Empty Set (or Null Set) doesn't have aren't any elements in it. It is empty.
Since every element of the superset is in the superset. Therefore, A superset contains all the subset of superset.
ii) Square root of 1/3 = √⅓
= ± √⅓ = +√⅓ or -√⅓
+√⅓ = +(√1/√3) = +(1/√3)
+√⅓ = +(1/1.7321)
+√⅓ = +0.577
Therefore Positive square root of 1/3 is 0.577 (A)
First we should figure out how many times 2 goes into 69,(because each tile is 2 feet long) and I am going to do that by dividing 69 by 2. I got 34.5, so we can just say 35 to make it easier. So we now know we need 35 tiles, but they come in boxes of 6, so we will need to divide 35 by 6. It didn't make a full number (it was 5.833) but we need a full number of tiles so we will round up.
Our final number of how many boxes of tiles is 6.
Here is the solution of the given problem above.
Given: Weight of single calf = weight of mother + 3.8%
Weight of mother = 3.75 tons or 7,500 pounds
? = weight of the calf
First, we need to find the 3.8% of 7,500 pounds. The result is 285 pounds.
So to get the weight of the calf, let's add 7,500 pounds to 285 pounds and the result is 7,785 pounds. So the weight of the calf is 7,785 pounds. Hope this helps.
20100 = 16000 * (1.02)^ t
20100/16000 = 1.02^t
1.25625 = 1.02^t
log 1.25625 = t * log 1.02
t = log 1.25625 / log 1.02
= 11.5