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m_a_m_a [10]
3 years ago
12

A breed of cattle needs at least 10 proteins and 8 fats units per day. Feed type I provides 6 protein and 2 fat units at $4 per

bag. Feed II provides 2 protein and 3 fat units at $3 per bag. Find the minimum cost.
Mathematics
1 answer:
Vikki [24]3 years ago
7 0
Let the number of bags of feed type I to be used be x and the number of bags of feed type II to be used be y, then:

We are to minimize:

C = 4x + 3y

subject to the following constraints:

6x+2y\geq10 \\  \\ 2x+3y\geq8 \\  \\ x\geq0,\ y\geq0

From the graph of the 4 constraints above, the corner points are (0, 5), (1, 2), (4, 0).

Testing the objective function for the minimum corner point we have:

For (0, 5):
C = 4(0) + 3(5) = $15

For (1, 2):
C = 4(1) + 3(2) = 4 + 6 = $10

For (4, 0):
C = 4(4) + 3(0) = $16.

Therefore, the combination that yields the minimum cost is 1 bag of type I feed and 2 bags of type II feed.
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Answer:

Option D that is y=-2(x+1) is the correct choice.

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y=2x-2

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Condition for one solution.

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