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3 years ago

Jerry has 4 pies with 10 Pieces in each one he eats 15 pieces in a week how many does he have left.

Mathematics

1 answer:

Rasek [7]3 years ago

7 0

Answer:

Step-by-step explanation:

4 pies multiplied by 10 slices gices 40 pieces in total. Subtract this by the amount he ate, 15, which gives 25.

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Brianna paid $13.77 for a new CD. The price includes a 6% sales tax. How much was the CD before the tax?

Lilit [14]

$12.94 is what the CD would be before the 6% sales tax

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3 years ago

Two numbers add up to 64. One of the numbers is 24. What is the other number?

goldfiish [28.3K]

Answer:

Step-by-step explanation:

If there are two numbers and you're trying to find the other one, you can subtract 64 and 24, you would get 40

Check; 40 + 24 = 64

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3 years ago

Which equation would you use to find x?

Nitella [24]

You would use B to find X

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3 years ago

the height of a plant in centimeters is modeled as a function of time, in days. consider this graph of the function enter the av

MrRa [10]

The average rate of change for the height of the plant measured in centimeters per day between day 0 and day 20 is 1.32 cm per day.

<h3>What is average height?</h3>

The average height is the ratio of change in height of the plant and the time taken taken for that change.

Given is the height of a plant in centimeters is modeled as a function of time, in days.

For day 0, the height is 18cm and the height for day 20 is 42 cm, then the average height change is

height per day = 42 - 18/ 20 -0

height per day = 1.2 cm/day

Thus, the average height of plant is 1.2 cm/day.

Learn more about average height.

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2 years ago

The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota

Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

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3 years ago