Answer:
the going to be answer A
Step-by-step explanation:
because the rhombus is moved down 2 and over 6 and was dilated by 2
The maximum height of an object is the greatest height the object can reach. The maximum height the rocket reaches is 40.2 feet
<h3>Vertex form of an equation</h3>
The maximum height of an object is the greatest height the object can reach. Given the equation that represent the height of the rocket.
f(t) = -15t² + 48t
The maximum height of the rocket occur at the point where:
t = -b/2a
t = -48/2(-15)
t =48/30
t = 1.6secs
Substitute t = 1.6 into the function as shown:
f(1.6) = -15(1.6)² + 48(1.6)
f(1.6) = -38.4 + 76.8
f(1.6) = 40.2
Hence the maximum height the rocket reaches is 40.2 feet
Learn more on maximum height here: brainly.com/question/12446886
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For this case we have the following system of equations:
5x + 3y = 17
-8x - 3y = 9
We can rewrite the system like:
Ax = b
Where,
A = [5 3; -8 -3]
b = [17; 9]
x = [x; y]
The determinant of matrix A is given by:
lAl = ((5) * (- 3)) - ((3) * (- 8))
lAl = (-15) - (-24)
lAl = -15 + 24
lAl = 9
Answer:
The determinant for solving this linear system is:
lAl = 9
93% of x = 198 tons
93% = 93/100
= 0.93
0.93 * x = 198 tons
Divide both sides by 0.93:
x = 198/0.93
x = 212.90 -> Final Answer.
8^2 + b^2 = 24^2
64 + b^2 = 576
-64 -64
b^2 = 512
Take the square root from b^2 and 512 =
b = 22.627
Answer 22.63 (rounded up)
