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OLga [1]
3 years ago
15

Find the total force on a piston of diameter 3.25 in., if the pressure (P) exerted on it is 150 lb/sq.In. Use 3.14 for and round

to the nearest 50 lbs.
Mathematics
1 answer:
skelet666 [1.2K]3 years ago
6 0

Answer:

1244 Ibf(Pounds force)

Step-by-step explanation:

The formula for Total force on a piston when given the diameter of the bore area =

F = P × π × d²/4

P = 150 lb/sq.In

π = 3.14

d = 3.25 in

Hence,

F = 150 lb/sq.In × 3.14 × 3.25 in /4

= 4974.9375 ÷ 4

= 1243.734375 Ibf(Pounds force)

Approximately = 1244 Ibf(Pounds force)

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Step-by-step explanation:

10 • 18 = 180

18 - 6 = 12

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180 + 30 + 30 = 240
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Answer:

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Step-by-step explanation:

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Use the net to find the lateral area of the prism.
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3 years ago
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

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Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

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m<EYL = 45

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blagie [28]

Answer

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Step-by-step explanation:

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