Answer:
B. 0.03110
Step-by-step explanation:
Given
Probability of Hit = 60%
Required
Determine the probability that he misses at 6th throw
Represent Probability of Hit with P
Convert to decimal
Next; Determine the Probability of Miss (q)
Opposite probabilities add up to 1;
So,
Substitute 0.6 for p
Next,is to determine the required probability;
Since, he's expected to miss the 6th throw, the probability is:
Hence;
<em>Option B answers the question</em>
Answer:
The sample statistic for the proportion of voters surveyed who said they'd vote for Brown is 0.308.
The expected numbers of voters who would vote for Brown is 3604.
Step-by-step explanation:
The sample statistic is a numerical quantity used to represent a characteristic of a sample. For example, sample mean is a sample statistic representing the average of the sample. Or, sample proportion is a sample statistic representing the proportion of a particular variable in the sample. Or sample variance is a sample statistic representing the variance of the sample.
The sample statistic can be used to estimate the population parameter.
They are known as the point estimate of the parameter.
The sample proportion of a variable <em>X</em> is given by:
It is provided that of the <em>n</em> = 250 registered voters selected, the number of voters who said they would vote for Brown is <em>X </em>= 77.
Compute the sample statistic for the proportion of voters surveyed who said they'd vote for Brown as follows:
Thus, the sample statistic for the proportion of voters surveyed who said they'd vote for Brown is 0.308.
Compute the expected number of people of the 11700 registered voters who would vote for Brown as follows:
Thus, the expected numbers of voters who would vote for Brown is 3604.