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3 years ago

To the nearest 1000 there are 18000 people at a festival write down the maximum possible number of people at the festival

Mathematics

1 answer:

damaskus [11]3 years ago

8 0

9514 1404 393

Answer:

18,499

Step-by-step explanation:

Any number greater than or equal to 18,500 will be rounded to a higher thousand. The maximum integer that will round to 18,000 is 18,499.

There could have been up to 18,499 people at the festival.

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A regular hexagon is shown below. Find the value of x.

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The measure of each interior angle of the hexagon is 120°. Then the value of x will be 20°.

<h3>What is a polygon?</h3>

The polygon is a 2D geometry that has a finite number of sides. And all the sides of the polygon are straight lines connected to each other side by side.

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Then the internal angle of the hexagon is (5x + 20)°.

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2 years ago

The additive inverse of 10 is -17. If 10 + (-17) = 0, then the numbers are additive inverses. True or False?

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3 years ago

PLEASE HELP!!! ASAP!!!!!!!!!!!!!!! 10 POINTS

I am Lyosha [343]

$1800|2\\.\ 900|2\\.\ 450|2\\.\ 225|5\\.\ \ 45|5\\.\ \ \ 9|3\\.\ \ \ 3|3\\.\ \ \ 1|\\\\1880=2\cdot2\cdot2\cdot5\cdot5\cdot3\cdot3=2^3\cdot5^2\cdot3^2\\\\Answer:\ \boxed{2^3\cdot3^2\cdot5^2}$

$\sqrt[3]{320}\\\\320|2\\160|2\\.\ 80|2\\.\ 40|2\\.\ 20|2\\.\ 10|2\\.\ \ 5|5\\.\ \ 1|\\\\320=2\cdot2\cdot2\cdot2\cdot2\cdo2\cdot5=2^3\cdot2^3\cdot5=2^3\cdot2^3\cdot\\\\\sqrt[3]{320}=\sqrt[3]{2^3\cdot2^3\cdot5}=\sqrt[3]{2^3}\cdot\sqrt[3]{2^3}\cdot\sqrt[3]{5}=2\cdot2\sqrt[3]{5}=4\sqrt[3]5\\\\Answer:\ \boxed{\sqrt[3]{320}=4\sqrt[3]{5}}$

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mafiozo [28]

Answer:

Amount she has now = $5.5

Step-by-step explanation:

Given:

Amount of Money had = $8

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Amount she has now

Computation:

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