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3 years ago

PLS HELP I WILL MARK BRAINLYEST !!!!!!

Mathematics

1 answer:

Ivan3 years ago

7 0

Answer:

the third option

Step-by-step explanation:

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Help me plss plss I really need help I have a f

Colt1911 [192]

Answer:

A. 5 1/2 and D. 11/2

Step-by-step explanation:

Make improper fraction

8*1+3=11/8

Solve by multiplying:

4*11/8

44/8

Simplified is 11/2

We can turn it back into a mixed number

2*5+1=11 so 5 1/2

6 0

3 years ago

A student received a coupon for 17% off the total purchase price at a clothing store. Let c be the

lys-0071 [83]

C - 0.17c = 0.83c
When you write “c” at the start, or x or whatever, it has an understood (invisible) number 1. So you’re subtracting the decimal on the next variable from 1.

7 0

3 years ago

What is the equation in slope-intercept form of a line that is perpendicular to y=2x+2 and passes through the point (4, 3)?

andriy [413]

Answer:

$y = - \frac{1}{2} x + 5$

Step-by-step explanation:

slope-intercept form

y= mx +c, where m is the slope and c is the y-intercept

Given line: y= 2x +2

slope= 2

The product of the slopes of perpendicular lines is -1. Let the slope of the unknown line be m.

m(2)= -1

m= -1 ÷2

m= -½

Substitute the value of m into the equation:

y= -½x +c

To find the value of c, substitute a pair of coordinates.

When x= 4, y= 3,

3= -½(4) +c

3= -2 +c

c= 3 +2

c= 5

Thus, the equation of the line is y= -½x +5.

7 0

3 years ago

HELP HELP HELP HELP 13 Points

nirvana33 [79]

The answer is 22 years old.
You set p = 2d then you solve for D. Then you do 2+p and set that equal to 3(d-5+2) then you solve. You keep going until you get P's age which is 22 and annie's age is 6.

6 0

3 years ago

Read 2 more answers

Differentiate Vx(x + 2) with respect to x.

Travka [436]

Answer:

$y'= \frac{3x+2}{2\sqrt{x} }$

General Formulas and Concepts:

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$y=\sqrt{x} (x+2)$

Step 2: Rewrite

$y=x^{\frac{1}{2} } (x+2)$

Step 3: Differentiate

Product Rule [Basic Power/Chain Rule]: $y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)$
Simplify: $y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}$
Rewrite: $y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}$
Add: $y'= \frac{3x+2}{2\sqrt{x} }$

7 0

3 years ago