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Feliz [49]
3 years ago
6

PLS HELP I WILL MARK BRAINLYEST !!!!!!

Mathematics
1 answer:
Ivan3 years ago
7 0

Answer:

the third option

Step-by-step explanation:

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Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the
Black_prince [1.1K]

Answer:

a)  P(2)=0.270

b) P(X>3)=0.605

c)  P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the  Poisson distribution:

\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}

a)  In this case: \lambda=2.1

P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270

Therefore, the probability is P(2)=0.270.

b)  In this case: \lambda=2\cdot 2.1=4.2

P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605

Therefore, the probability is P(X>3)=0.605.

c)  We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

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