A rectangle has an area of 384 m². The length and the width of the rectangle are changed by a scale factor of 0.75.
2 answers:
We are tasked to solve for the area of the new rectangle. The formula of solving area of the rectangle is A = width * length
Old triangle Area = 384 m² = w * l
New triangle Area we have:
Area = w * 0.75l
384 m² = w*0.75l
384 / 0.75 = w*l
288 m² = w*l
The answer is 288 m².
Answer: ![216\ m^2](https://tex.z-dn.net/?f=216%5C%20m%5E2)
Step-by-step explanation:
A rectangle has an area of 384 m².
Let l and w are the length and the width of the original rectangle, such that the area of the rectangle is given by ;-
![A=lw=384](https://tex.z-dn.net/?f=A%3Dlw%3D384)
The length and the width of the rectangle are changed by a scale factor of 0.75 will be:
![l'=0.75l\\\\w'=0.75w](https://tex.z-dn.net/?f=l%27%3D0.75l%5C%5C%5C%5Cw%27%3D0.75w)
Now, the area of the new rectangle will be :
![A=l'w'=0.75l\times0.75w\\\\=(0.75)^2(lw)\\\\=(0.5625)(384)=216\ m^2](https://tex.z-dn.net/?f=A%3Dl%27w%27%3D0.75l%5Ctimes0.75w%5C%5C%5C%5C%3D%280.75%29%5E2%28lw%29%5C%5C%5C%5C%3D%280.5625%29%28384%29%3D216%5C%20m%5E2)
Hence, the area of the new rectangle![=216\ m^2](https://tex.z-dn.net/?f=%3D216%5C%20m%5E2)
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