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emmainna [20.7K]
4 years ago
11

Can someone help me thank u

Mathematics
2 answers:
MAXImum [283]4 years ago
8 0
Your right!
good job!

Snowcat [4.5K]4 years ago
5 0
It is A.
You know this because it is always n-1. (:
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Disregard my work, but how do you get the answer? There is also a graph at the bottom which is optional to use.
kakasveta [241]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)=  A(  Bx+  C)+  D
\\\\
~~~~y=  A(  Bx+  C)+  D
\\\\
f(x)=  A\sqrt{  Bx+  C}+  D
\\\\
f(x)=  A(\mathbb{R})^{  Bx+  C}+  D
\\\\
f(x)=  A sin\left( B x+  C  \right)+  D
\\\\
--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\
\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }  B\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{  C}{  B}\\
~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }  D\\
~~~~~~if\   D\textit{ is negative, downwards}\\\\
~~~~~~if\   D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{  B}

with that template in mind.

since the original or "parent" function is y = x²−4x+3, if we change the "x" argument to "x-2", we end up with a horizontal shift.

the x-2 part would be in the template the Bx+C part, with B = 1 and C = -2, or a horizontal shift to the right of 2/1 or 2 units.

since the parent function has a point at (2, -1), if we move that horizontally only to the right, we'd end up at (4, -1).
7 0
4 years ago
Tom is trying to write 3/61 as a decimal. He used long division and divided until he got the quotient 0.0491803279, at which poi
PilotLPTM [1.2K]
45,678,689 & [56 witch I think
5 0
4 years ago
Read 2 more answers
HURRY IM TAKING A TEST!!!!!!!! Which table of ordered pairs represents a proportional relationship?
SashulF [63]

Answer:

D

Step-by-step explanation:

They are all multiplied by 3 which is proportional

4 0
4 years ago
Pls help the person with the correct answer gets a brainliest
borishaifa [10]

Answer:

21

Step-by-step explanation:

Good luck ..have a nice day

3 0
3 years ago
A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two
Oliga [24]

Let

x-------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of the rectangle is equal to

A=x*y

The area of the two congruent right triangles  is equal to the area of the rectangle

A=2*44=88\ in^{2}

so

88=x*y -------> equation A

y=x-3 -----> equation B

Substitute equation B in equation A

x*[x-3]=88

x^{2} -3x-88=0 --------> equation that can be used  to solve for the length of the rectangle

Using a graph tool-------> solve the quadratic equation

see the attached figure

The solution is

x=11\ in -----> the length of the rectangle

Find the value of y

88=11*y

y=8\ in  ----> the width of the rectangle

Statements

<u>case A)</u> The area of the rectangle is 88 square inches

The statement is True

See the procedure

<u>Case B)</u> The equation  x*[x-3]=44 can be used to solve for the dimensions of the triangle

The statement is False

Because, the equation x*[x-3]=88 can be used to solve for the dimensions of the triangle

<u>case C)</u> The equation x^{2} -3x-88=0 can be used to solve for the length of the rectangle

The statement is True

see the procedure

<u>case D)</u>The triangle has a base of 11 inches and a height of 8 inches

The statement is True

Because, the base of the triangle is equal to the length of the rectangle and the height of the triangle is equal to the width of the rectangle

<u>case E)</u> The rectangle has a width of 4 inches

The statement is False

See the procedure

8 0
3 years ago
Read 2 more answers
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