Question

Help me pleasee , timed

Answer 1

Answer:

Option 2: $x^{9}(\sqrt[3]{y})$

Step-by-step explanation:

Given

$(x^{27}y )^{\frac{1}{3} }$

The exponent power will be multiplied with the powers inside the bracket

So,

$(x^{27 * \frac{1}{3}} y^{\frac{1}{3}})$

$= x^{\frac{27}{3}} y^{\frac{1}{3} }$

$= x^{9} y^{\frac{1}{3}}$

Writing in radical form will give us:

$x^{9}(\sqrt[3]{y})$

So,

Option 2 is the correct answer ..

Answer 2

Answer:

The second alternative is correct

Step-by-step explanation:

We have been given the expression;

$(x^{27}y)^{\frac{1}{3}}$

The above expression can be re-written as;

$(x^{27})^{\frac{1}{3}}*y^{\frac{1}{3}}\\\\(x^{27})^{\frac{1}{3}}=x^{27*\frac{1}{3}}=x^{9}$

On the other hand;

$y^{\frac{1}{3}}=\sqrt[3]{y}$

Therefore, we have;

$x^{9}\sqrt[3]{y}$