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Simora [160]
3 years ago
13

the diameter of a cicrle is 72.4 millimeters . find the area of this circle in square millimeters. round your answer to the appr

opriate number of significant
Mathematics
1 answer:
Temka [501]3 years ago
4 0

Answer:

4,116.9mm² (rounded up to nearest one decimal point)

Step-by-step explanation:

Diameter of a circle is 72.4mm (where mm stands for millimeters)

Area of a circle is given by πr²

Radius (r) = 72.4mm ÷ 2 = 36.2mm

Area = π × (36.2mm)² = 4,116.868677mm²

That is  4,116.9mm² (rounded up to one decimal point)

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PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS
Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\

With respect to reference angle A, we have:

  • opposite side = a = 4
  • adjacent side = b = \sqrt{33}
  • hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\

Then cosine which is adjacent over hypotenuse

\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\

Tangent is the ratio of opposite over adjacent

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

  • cosecant, abbreviated as csc, is the reciprocal of sine
  • secant, abbreviated as sec, is the reciprocal of cosine
  • cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{  ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

------------------------------------------------------

Summary:

The missing side is b = \sqrt{33}

The 6 trig functions have these results

\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0
1 year ago
Express the area of this triangle as monomial.
gladu [14]

The formula of an area of a triangle:

A=\dfrac{1}{2}bh

b - base

h - height

We have b = 8x and h = 7x. Substitute:

A=\dfrac{1}{2}(8x)(7x)=(4x)(7x)=28x^2

<h3>Answer: 28x²</h3>
5 0
3 years ago
Solve for p<br> 3(p + q) = p<br> A. q = -2/3p<br> B. q = -3/2p<br> C. p = -2/3q<br> D. p = -3/2q
Tasya [4]
It’s A! hope this helps you out!
8 0
3 years ago
Someone help please?
disa [49]
There is the answer my guy it’s a picture

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4 0
3 years ago
ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to kno
Ber [7]

Answer:

70 fries and 35 shakes

Step-by-step explanation:

ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to know which sells better but they lose track of what they sold. They know 105 students bought either fries or a shake. They count their money and it’s $245. How many fries (x) and shakes (y) did they sell?

f = fries

s = shakes

To solve this we need to make two equations. Those equations being: f+s = y and 2f+3s = y. Now we will plug in all the values. f + s = 105 and 2f + 3s = 245. Now we will subtract f from 105 to get s. this makes s =105-f. We can then plug this into the other equation making the other equation: 2f+ 3(105-f) = 245. Now we will simplify this to get: 2f + (315 -3f) = 245. When we simplify it further we get: 315-f = 245.Now we will subtract 315 from both sides to get: -f = -70. now divide both sides by -1 and we get f = 70. Now we can plug that into the f+ s = y equation. 70 + s = 105. Subtract 70 from both sides and we have s. S = 35

6 0
2 years ago
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