The zeros are 5, and -1/9. The second option is correct. Hope my work helps!
Realistic occupations which is letter b
Given:
P: (2,0,5)
L: (0,6,4)+t(7,-1,5)
and required plane, Π , passes through P and perpendicular to L.
The direction vector of L is V=<7,-1,5>.
For Π to be perpendicular to V, Π has V as the normal vector.
The equation of a plane with normal vector <7,-1,5> passing through a given point P(xp,yp,zp) is
7(x-xp)-1(y-yp)+5(z-zp)=0
Thus the equation of plane Π passing through P(2,0,5) is
7(x-2)-y+5(z-5)=0
or alternatively,
7x-y+5z = 14+25
7x-y+5z = 39
Answer:
(x-2)(x+4)
Step-by-step explanation:
So it would be A.
Explanation: The middle number is 2 and the last number is -8.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get 2
Multiply together to get -8
Can you think of the two numbers?
Try -2 and 4:
-2+4 = 2
-2*4 = -8
Fill in the blanks in
(x+_)(x+_)
with -2 and 4 to get...
(x-2)(x+4)
Answer:
(x−2)(x+4)
Answer:
Step-by-step explanation:
4x - 2y = 6
-2y = -4x + 6
y = -4x/-2 + 6/-2
y = 2x - 3
