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3 years ago

Write and solve an equation with the numbers 0 and 9. Then write an equation with the numbers 1 and 9 that has the same answer

Mathematics

2 answers:

tiny-mole [99]3 years ago

8 0

0+9=9
1*9=9
0 plus any number equals that number. 1 multiplied by any number equals that number

Vsevolod [243]3 years ago

3 0

Answer:

0+9=9

1 x 9=9

Step-by-step explanation:

Here, we have to write a kind of equation with 0 and 9

And 1 and 9

So, as to create same result

We know that 0 is the additive identity

Hence, 0+9=9

And 1 is the multiplicative identity

Hence, 1 x 9=9

Therefore, 0+9 and 1 x 9 will give the same result.

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inysia [295]

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Step-by-step explanation:

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For the line that passes through Y(3,0), parallel to DJ with D(-3,1) and J(3,3), complete the following: Find the slope. Write a

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1 year ago

Y-9=3/4(x+8) rewrite it in slope intercept form explain your answer.

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3 years ago

Find the distance from the origin to the graph of 4x-y+8=0

kupik [55]

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4 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago