Server farms such as Google and Yahoo! provide enough compute capacity for the highest request rate of the day. Imagine that mos
t of the time these servers operate at only 60% capacity. Assume further that the power does not scale linearly with the load; that is, when the servers are operating at 60% capacity, they consume 90% of maximum power. The servers could be turned off, but they would take too long to restart in response to more load. A new system has been proposed that allows for a quick restart but requires 20% of the maximum power while in this "barely alive" state. a. How much power savings would be achieved by turning off 60% of the servers? b. How much power savings would be achieved by placing 60% of the servers in the "barely alive" state? c. How much power savings would be achieved by reducing the voltage by 20% and frequency by 40%? d. How much power savings would be achieved by placing 30% of the servers in the "barely alive" state and 30% off?
1 answer:
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Answer:
The code to calculate the area of a circle is:
from math import pi
def circleArea(radius):
if radius > 0:
return pi * (radius ** 2)
else:
return None
if __name__ == '__main__':
radius = 5
print("Radius: {} Area: {}".format(radius,circleArea(radius)))
Explanation:
A detailed explanation of each line of code is given below.
#Define the number pi used to calculate the area
from math import pi
#We define a function that calculates the area of a circle
def circleArea(radius):
#Check if the radius is valid ( radius > 0) since there aren´t negative radius
if radius > 0:
#Compute the area formula for a circle
return pi * (radius ** 2)
else:
#Return None if the radius is invalid
return None
#Run the function we´ve defined
if __name__ == '__main__':
#Define a radius
radius = 5
#Call the function and parse the radius through it, then print the result
print("Radius: {} Area: {}".format(radius,circleArea(radius)))