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CaHeK987 [17]
4 years ago
12

Server farms such as Google and Yahoo! provide enough compute capacity for the highest request rate of the day. Imagine that mos

t of the time these servers operate at only 60% capacity. Assume further that the power does not scale linearly with the load; that is, when the servers are operating at 60% capacity, they consume 90% of maximum power. The servers could be turned off, but they would take too long to restart in response to more load. A new system has been proposed that allows for a quick restart but requires 20% of the maximum power while in this "barely alive" state. a. How much power savings would be achieved by turning off 60% of the servers? b. How much power savings would be achieved by placing 60% of the servers in the "barely alive" state? c. How much power savings would be achieved by reducing the voltage by 20% and frequency by 40%? d. How much power savings would be achieved by placing 30% of the servers in the "barely alive" state and 30% off?

Computers and Technology
1 answer:
EleoNora [17]4 years ago
3 0

Answer:

a) Power saving = 26.7%

b) power saving = 48%

c) Power saving = 61%

d) Power saving = 25.3%

Explanation:

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Int side1;
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Answer:

int width_A, width_B, len_A, len_B;

float rw, rl;

rw = (float)(width_A/width_B);

rl = (float)(len_A/len_B);

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else

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Explanation:

The width of the first triangle i call width_A.

The width of the second triangle i call width_B.

The length of the first triangle i call len_A.

The length of the second triangle i call len_B.

The ratio of the width i call rw.

The ratio of the length i call rl.

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The code is:

int width_A, width_B, len_A, len_B;

float rw, rl;

rw = (float)(width_A/width_B);

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if(rw == rl)

printf("They are similar");

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