1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ExtremeBDS [4]
3 years ago
14

In the figure, PR = 15x – 11 and PQ = 3x + 6. Find QR in terms of x.

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer: 12x - 17

Step-by-step explanation:

To find QR subtract PQ from PR

15x-11 -(3x+6) ---> 15x - 11 - 3x -6 = 12x -17

You might be interested in
Abby can buy individual songs for $1.00 to download, or she can
Taya2010 [7]

The solution to the inequalities x + 8y ≤ 50, x ≤ 30, y > 2 is the darker region shown on the graph.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the number of individual songs and y represent the number of albums, hence:

x + 8y ≤ 50   (1)

x ≤ 30    (2)

y > 2   (3)

The solution to the inequalities x + 8y ≤ 50, x ≤ 30, y > 2 is the darker region shown on the graph.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0
1 year ago
Please help im so confused​
slava [35]

Answer:

\text{1. }50^{\circ}\\\text{2. }80^{\circ}

Step-by-step explanation:

1. The measure of an inscribed angle is always half the measure of the arc it forms. Since angle ACB forms arc AB with a measure of 100 degrees, the measure of angle ACB will be equal to \frac{100}{2}=\boxed{50^{\circ}}.

2. Relating to problem 1, both inscribed angles marked in the figure form the same arc. All inscribed angles forming the same arc will have the same measure. Therefore, the measure of angle GEF is equal to \boxed{80^{\circ}}.

3 0
2 years ago
Solve for me pleasee​
DerKrebs [107]

Answer:

80°=x°[by alternate exterior angle]

3 0
3 years ago
Read 2 more answers
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
2 years ago
WANT POINTS JUST ANSWER THIS CORRECTLY FOR 45!!!
Lelu [443]
Since we’re trying to find minutes, concert all known information to minutes

1 hr 15 mins = 75 mins
1 hr 30 mins = 90 mins

Next, calculate how many total minutes Gage has skated in the first 8 days

75(5) + 90(3) = 645 mins

Create an equation to find the average of Gage’s minutes of skating. Add up all the minutes and divide by the total amount of days and set equal to 85, the average we are trying to get.

(645 mins + x mins)/9 days = 85

Solve for x

645 + x = 765
x = 120

So, in order to have an average of an 85 minute skate time, Gage would need to skate 120 minutes on the ninth day.
3 0
2 years ago
Other questions:
  • What is the answer to this problem?
    10·1 answer
  • How much compound interest will $50,000 earn in 10 years at 3.4% APR compounded yearly, providing no deposits or withdrawals are
    12·2 answers
  • Simplify the following: (-1+4)^3+5×7
    10·2 answers
  • An architect is designing a deck. It will
    9·1 answer
  • an emu is 57 inches tall 75 inchess less than an 6 times height of an kakapoo what is the height of a kakapoo in inches
    15·1 answer
  • 9|r-2|-10&lt;-73<br> any one can solve
    5·1 answer
  • In how many ways can a committee of
    6·1 answer
  • Please help me with My algebra. I'm stressing a lot right now so Thank you.
    9·1 answer
  • URGENT PLEASE HELP WILL GIVE BRAINLEIST !!!!!!!!!!
    6·2 answers
  • If 7 cakes cost 15 how much 22 cakes cost pllsssss help with this ik this problem is easy but i just cant solve it so help
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!