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3 years ago

8

A number minus seven is nine.

1 answer:

lukranit [14]3 years ago

5 0

Answer:

Your answer would be 16 - 7 = 9.

You can simply add the two numbers and it would still give you the same answer, but I decided to just look for the number.

Step-by-step explanation:

I hope this helped solve your question.

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This beach ball has a surface area of 615.44 inches². What is its diameter? Use 3.14 for π.

aleksandr82 [10.1K]

Answer:

7

Step-by-step explanation:

6 0

3 years ago

5 & 2/8 - 3 &7/8 = ?

miv72 [106K]

Answer:

11/8 or 1 & 3/8

Step-by-step explanation:

5 & 2/8=21/4

3&7/8=31/8

21/4-31/8=11/8 or 1 & 3/8

4 0

3 years ago

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Roberto had $88, which is eleven times as much money as Bianca had. How much money did Bianca have? Select the correct solution

Alexandra [31]

Answer:

I think it is A

Step-by-step explanation:

Because it would be 88=11x the you would divide 11x by 11 to get x the 88 divided by 11= 8 so, Thus saying x=8

6 0

4 years ago

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(x-4)/(2x+1)-3 can you help me with this question

lilavasa [31]

Answer:

$\frac{(x - 4)}{(2x + 1)} - 3$ $=$ $\frac{-7x- 7}{3x + 1}$

Step-by-step explanation:

Given

$\frac{(x - 4)}{(2x + 1)} - 3$

Required

Solve

Express 3 as a fraction

$\frac{(x - 4)}{(2x + 1)} - \frac{3}{1}$

Take LCM

$\frac{x - 4 - 3(2x + 1)}{3x + 1}$

$\frac{x - 4 - 6x - 3}{3x + 1}$

Collect Like Terms

$\frac{x - 6x- 4 - 3}{3x + 1}$

Simplify like terms

$\frac{-7x- 7}{3x + 1}$

Hence:

$\frac{(x - 4)}{(2x + 1)} - 3$ $=$ $\frac{-7x- 7}{3x + 1}$

4 0

3 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

3 years ago

Read 2 more answers