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1 year ago

Find the ratio of the trig function indicated.

Mathematics

1 answer:

Andrew [12]1 year ago

5 0

Answer:

$\huge\boxed{\bf\:Ratio = 4:5}$

Step-by-step explanation:

We have a right angled triangle given.

At first, let's note that, sin θ = oppposite side of the triangle / hypotenuse of the triangle.

Now, in the given triangle, from the view of ∠θ,

Opposite side of the triangle = 8
Hypotenuse = 10

Then,

$\sin \theta = \mathrm{\frac{opposite \: side}{hypotenuse}}\\\sin\theta = \frac{8}{10}\\\sin\theta = \frac{4}{5}\\\\\\\Longrightarrow \boxed{\mathrm{Ratio = 4:5}}$

$\rule{150pt}{2pt}$

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In the equivalent ratios 4:7 and 48:x, what is the value of x?

kykrilka [37]

Answer: 84

Step-by-step explanation: 48÷4= 12 so 12 times 7 is 84

5 0

2 years ago

What is the range of possible sizes for side x?<br><br><br> 8.8

eduard

Answer:

The size of side x can range from 0.5 < x < 16.5.

The size of side x cannot take on values 0 and 16.5, but it ranges between those two values for side x to complete a triangle with those two other sides.

Step-by-step explanation:

Complete Question

What is the range of possible sizes for side x? One Side is 8.5 the other is 8.0.

Solution

With the logical assumption that the three sides are to form a triangle

Let the two sides given be y and z

And the angle between y and z be θ

The angle θ can take on values from 0° to 180° without reaching either values.

As θ approaches 0°, (x+z) becomes close to equaling y. (x + z) < y

It can never equal y, because θ can never be equal to 0°, if a triangle is to exist.

Hence, x > (z−y)

x > 8.5 - 8.0

x > 0.5

As θ approaches 180°, x approaches the sum y+z, θ can never equal 180° if a triangle is to exist, so x never equals (y+z).

Hence x < (y+z)

x < 8 + 8.5

x < 16.5

Hope this Helps!!!

3 0

2 years ago

5 days 6 hours 20 minutes minus 3 days 8 hours 40 minutes plz help will make brainliest

Blababa [14]

Answer:

1 day 21 hours 40 minutes

Step-by-step explanation:

5 days 6 hours 20 minutes

- 3 days 8 hours 40 minutes

============================

We will need to borrow minutes from the hours because we don't have enough.

1 hour = 60 minutes

6-1 = 5 hours

20 +60 = 80 minutes

5 days 5 hours 80 minutes

- 3 days 8 hours 40 minutes

==========================

We will need to borrow hours from the days because we don't have enough.

1 day = 24 hours

5 -1 =4 days

5 + 24 = 29 hours

4 days 29 hours 80 minutes

- 3 days 8 hours 40 minutes

==========================

1 day 21 hours 40 minutes

7 0

3 years ago

Read 2 more answers

The width of a rectangle is 4 feet and the diagonal length of he rectangle is 13 feet what is the measurement is the closest to

AURORKA [14]

Answer:

The length is APPROXIMATELY equal to 12.4.

Step-by-step explanation:

Use the converse of the Pythagorean Theorem ( $a^{2}$ + $b^{2}$ = $c^{2}$ [where "c" is both the longest side and the hypotenuse]) since a rectangle's diagonals will always cut it into two right triangles:

$13^{2} = 169$

$4^{2} =16$

169-16=153.

$\sqrt{153}$ ≈ 12

$\sqrt{153}=12.36931688$

or if the problem has to be exact (using radicals)

3* $\sqrt{17}$

I hope this helps ;)

8 0

2 years ago

F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x

olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

$V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy$

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

$V=9\int\limits^2_0 {4y^{3}/3} \, dy$

After performing the elementary y integral we obtain the desired volume as below,

$V= 48 units^{3}$

4 0

2 years ago