Question

(x-4)/(2x+1)-3 can you help me with this question

Answer 1

Answer:

$\frac{(x - 4)}{(2x + 1)} - 3$ $=$ $\frac{-7x- 7}{3x + 1}$

Step-by-step explanation:

Given

$\frac{(x - 4)}{(2x + 1)} - 3$

Required

Solve

Express 3 as a fraction

$\frac{(x - 4)}{(2x + 1)} - \frac{3}{1}$

Take LCM

$\frac{x - 4 - 3(2x + 1)}{3x + 1}$

$\frac{x - 4 - 6x - 3}{3x + 1}$

Collect Like Terms

$\frac{x - 6x- 4 - 3}{3x + 1}$

Simplify like terms

$\frac{-7x- 7}{3x + 1}$

Hence:

$\frac{(x - 4)}{(2x + 1)} - 3$ $=$ $\frac{-7x- 7}{3x + 1}$