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kupik [55]
4 years ago
8

Zoya has to earn at least $300 to meet her fundraising goal. She has only 100 bracelets that she plans to sell at $5 each. Which

inequality shows the number of bracelets, x, Zoya can sell to meet her goal?
60 ≤ x ≤ 100

60 ≤ x ≤ 300

100 ≤ x ≤ 300

20 ≤ x ≤ 100
Mathematics
2 answers:
MrMuchimi4 years ago
8 0
    If she wants to meet the goal she have to sell:  $ 300 : $5 = 60 bracelets. This is the minimum she must sell and the maximum is 100.
    Therefore inequality is:
    A ) 60 ≤ x ≤ 100

crimeas [40]4 years ago
6 0
60 <= x <= 100 because 1) $300÷$5 = 60 ; 2) <span>She has only 100 bracelets;</span>
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Taken together, we find that (0, 0, 0) appears to be the only critical point on f within the ball. At this point, we have f(0,0,0)=0.

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)

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L_x=5yz+2\lambda x=0
L_y=5xz+2\lambda y=0
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5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}
5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}

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