Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30 What I did next was divide thirty by the number of cracker and also by the number of can of juice.
120÷30= 4
90÷30= 3
So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.
I hope you enjoyed my explanation. :)
Answer: 4.3478 or 100/23
Step-by-step explanation:
Set the y values equal to each other since they are the same unknown (x). You end up with 100=23x, solve for x. Move the 23 over to the other side by using division. x=100/23. If you need it in decimal form, 100÷23=4.347826087
For what shape??
pls answer, then we can get somewhere with this question!! :)
Answer: 12c+16d
Step-by-step explanation: 4(3c+4d)
(4)(3c+4d)
(4)(3c)+(4)(4d)
12c+16d
