Zachary is solving the following equation.Which is the best first step to begin to simplify the equation?

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

3 years ago

What is the average rate of change of f over the interval -7 < or equal to x Give an exact number

Annette [7]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

The average rate of change can be found by using the following formula

$\frac{f(x_{2}) - f(x_{1}) }{x_{2} - x_{1}}$

Since the interval goes from -7 to 2, we should find the y-values that correspond to x=-7 and x=2.

By inspection of the graph, we can clearly see that when x is -7, y is -7 as well and when x is 2, y is 5.

Now that we know this, we can simply plug these values into the formula!

$\frac{f(2) - f(-7) }{2 - (-7)} = \frac{5 - (-7)}{2 - (-7)} = \frac{5 +7}{2+7} = \frac{12}{9} = \frac{4}{3}$

Good luck!

3 0

3 years ago

The measure of an inscribed circle of an angle is the measure of the intercepted arc

Andre45 [30]

Answer:

(the statement does not appear to be true)

Step-by-step explanation:

I don't think the statement is true, but you CAN compute the intercepted arc from the angle.

Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.

Therefore, adding the angles together, we have:

alpha + 90 + 90 + <FDG = 360

Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)

4 0

3 years ago

The energy released by metabolism of 1 average candy bar is 1 x 10^6 joules.

Elis [28]

Answer: 32

Step-by-step explanation:

Given: The energy needed for 1 hour of running for an adult $=4.5\times10^6\ joules.$

Therefore. the energy needed for seven hours of running= $=7\times4.5\times10^6\ joules.=31.5\times10^6\ joules$

Since, he energy released by metabolism of 1 average candy bar $=1\times10^6\ joules.$

Therefore, the number of candy bars an adult need to eat to supply the energy needed for seven hours of running.= $\frac{31.5\times10^6}{1\times10^6}=31.5\approx32$

Hence, the adult need to eat 32 candies to supply the energy needed for seven hours of running.

3 0

3 years ago

We know that side NM is parallel to side XZ. If we consider side NY the transversal for these parallel lines, we create angle pa

Likurg_2 [28]

See the picture attached.

We know:
NM // XZ
NY = transversal line
∠YXZ ≡ ∠YNM

1) We know that ∠XYZ is congruent to ∠NYM by the reflexive property.

The reflexive property states that any shape is congruent to itself.
∠NYM is just a different way to call ∠XYZ using different vertexes, but the sides composing the two angles are the same.
Hence, ∠XYZ ≡ ∠NYM by the reflexive property.

2) ΔXYZ is similar to ΔNYM by the AA (angle-angle) similarity theorem

The AA similarity theorem states that if two triangles have a pair of corresponding angles congruent, then the two triangles are similar.
Consider ΔXYZ and ΔNYM:
∠YXZ ≡ ∠YNM
∠XYZ ≡ ∠NYM
Hence, ΔXYZ is similar to ΔNYM by the AA similarity theorem.

8 0

3 years ago

Read 2 more answers