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Julli [10]
3 years ago
6

Hello can you please help me posted picture of question

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0
Since the order of selection does not matter we will use combinations to solve this problem.

Total number of students = 20
Number of students to be selected = 4

We are to find the combinations of 20 objects taken 4 at a time. This can be expressed as 20C4

20C4 = 4845

Thus, there are 4845 ways to select the 4 students.

So, the correct option is D
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8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
divide 30 by 6. this gives you your answer. m=-5, because -30 divided by 6 equals -5.
now to test it you can plug -5 into the equation in place of M. 8 times -5 equals -40, plus 27 equals -13. 2 times -5 equals -10 plus -3 equals -13.
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