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3 years ago

5

Evaluate log4 16. (2 points) −4 −2 2 4

2 answers:

aleksley [76]3 years ago

7 0

Answer:

The correct option is 3. The value of given expression is 2.

Step-by-step explanation:

The given expression is

$log_4{16}$

Rewrite the given expression.

$log_4{4^2}$

According to the property of log.

$log_aa^x=x$

Using the property of log, we get

$log_4{4^2}=2$

Therefore the value of given expression is 2 and option 3 is correct.

soldi70 [24.7K]3 years ago

6 0

Log with the base of 4 of 16 is 2

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Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.

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3 years ago

A carpenter purchased 70ft of redwood and 70ft of pine for a total cost of $282. A second purchase, at the same prices, included

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3 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

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3 years ago