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3 years ago

Solve for x. 3x+10−−−−−−√=x+4

Mathematics

1 answer:

Contact [7]3 years ago

3 0

Answer:

16+^

Step-by-step explanation:

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What is 20% tip on a bill of 59.61

Ugo [173]

Answer:

about $12

Step-by-step explanation:

59.61(0.20)=11.922

11.922 rounded up is 12.

ur total bill would be $71.61

5 0

3 years ago

In △ABC, point M is the midpoint of AB , point D∈ AC so that AD:DC=2:5. If AABC=56 yd2, find ABMC, AAMD, and ACMD.

Komok [63]

Since point M is the midpoint of AB, then AM=MB.

Consider the area of the triangles ABC and BMC:

$A_{ABC}=\dfrac{1}{2}\cdot AB\cdot h_c=56\ yd^2,$

where $h_c$ is the height drawn from the vertex C to the side AB.

So, $AB\cdot h_c=112\ yd^2.$

Now

$A_{BMC}=\dfrac{1}{2}\cdot BM\cdot h_c=\dfrac{1}{2}\cdot \dfrac{AB}{2}\cdot h_c=\dfrac{1}{4}\cdot AB\cdot h_c=\dfrac{1}{4}\cdot 112=28\ yd^2.$

Also

$A_{AMC}=A_{ABC}-A_{BMC}=56-28=28\ yd^2.$

Now consider the area of the triangles AMD and CMD. Let $h_M$ be the height drawn from the point M to the side AC.

$A_{AMD}=\dfrac{1}{2}\cdot AD\cdot h_M=\dfrac{1}{2}\cdot \dfrac{2AC}{7}\cdot h_M=\dfrac{2}{7}\cdot \left(\dfrac{1}{2}\cdot AC\cdot h_M\right)=\dfrac{2}{7}\cdot A_{AMC}=\dfrac{2}{7}\cdot 28=8\ yd^2.$

Therefore,

$A_{MDC}=A_{AMC}-A_{AMD}=28-8=20\ yd^2.$

Answer: $A_{MBC}=28\ yd^2, A_{AMD}=8\ yd^2, A_{MDC}=20\ yd^2.$

5 0

3 years ago

Read 2 more answers

The area of a rectangle is at most 21 square inches. The width of the rectangle is 3.5 inches. What are the possible measurement

Afina-wow [57]

3.5x is lessthan or equal to 21

3.5x<=21 divide by 3.5

x<=6 so that means the length of the rectangle can be 6 or less.

8 0

3 years ago

What is the arc length of a circle (in meters) with a radius of 2 meters that has an arc angle of 90°? A 2π B π C 2 D 4π

Musya8 [376]

$\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad de grees\\ 
------\\
r=2\\
\theta =90
\end{cases}\implies s=\cfrac{(90)\pi (2)}{180}\implies s=\pi$

7 0

4 years ago

If a line has slope a, what is the slope of its reflection across the line y=x?

aleksandrvk [35]

Check the picture below.

notice the reflected gray line on the red one over the y=x line, the slope of either line across the y=x line is simply the other's upside-down.

$\stackrel{\textit{slope of line "a"}}{a\implies \cfrac{a}{1}}\hspace{5em}\stackrel{\textit{slope of its reflection}}{\cfrac{1}{a}}$

3 0

2 years ago