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Black_prince [1.1K]
3 years ago
12

Which ordered pair is on the graph of the function? (-6, 4) (-1, 2) (-2, -4) (6, -3)

Mathematics
2 answers:
VikaD [51]3 years ago
8 0

Answer:

(-6,4) hope that helps you it's that in the y there is two 4

ASHA 777 [7]3 years ago
6 0
The answer
Is :(-6,4)
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Find the value of x<br><br> (look at screenshot below)
Black_prince [1.1K]

Answer:

x = 25

Step-by-step explanation:

120 = 70 + 2x

120 - 70 = (70 - 70) + 2x

50 = 2x

50/2 = 2x/2

x = 25

5 0
3 years ago
Read 2 more answers
Autumn bought 4 pairs of jeans for her kids and one shirt for herself. The shirt cost $16.99. She spent a total of $108.95. What
klio [65]

Answer:

Each Jean cost $22.99

Step-by-step explanation:

First you would subtract the cost of the shirt from the total.

108.95-16.99=91.96

Then you would divide the 91.96 by 4 to get the cost for each Jean.

91.96/4=22.99

j=$22.99

6 0
3 years ago
two verticies of paralellogram ABCD are A(-6,-1) and B(-5,3). The intersection of the diagonals, E, are (-2, 1/2). Determine the
masya89 [10]

Answer:

D(2,2)

Step-by-step explanation:

The diagonals of a parallelogram gram bisects each other.

Therefore E is the midpoint of AD.

Let the coordinates of D be (a,b).

By the midpoint rule:

( \frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}) = ( - 2, \frac{1}{2} )

This implies that:

( \frac{ - 6+a}{2} ,\frac{ - 1+b}{2}) = ( - 2, \frac{1}{2} )

This implies that:

( \frac{ - 6+a}{2} =  - 2 ,\frac{ - 1+b}{2} =  \frac{1}{2} )

( - 6+a =- 4 , - 1+b = 1 )  \\ ( a =- 4 + 6 , b = 1 + 1 )  \\ ( a =2 , b =2 )

7 0
3 years ago
What is the surface area of this triangular pyramid? 3 m 3 m 3 m 3 m 2.6 m​
tekilochka [14]

\stackrel{\textit{3 standing triangles}}{3\left[\cfrac{1}{2}(\stackrel{b}{3})(\stackrel{h}{3}) \right]}~~ + ~~\stackrel{\textit{triangular base}}{\cfrac{1}{2}(3)(2.6)}\implies 13.5~~ + ~~3.9\implies 23.4~m^2

4 0
3 years ago
assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
melomori [17]

Given:

x and y are both differentiable functions of t.

4x^2+3y^3=28

x=-1\text{ and }\dfrac{dy}{dt}=8

To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

4x^2+3y^3=28       ...(i)

At x=-1,

4(-1)^2+3y^3=28

4+3y^3=28

3y^3=28-4

3y^3=24

Divide both sides by 3.

y^3=8

Taking cube root on both sides.

y=2

So, y=2 at x=-1.

Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

-8\dfrac{dx}{dt}+9(4)(8)=0

-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

6 0
3 years ago
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