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3 years ago

PLEASE HELP!! I WILL GIVE BRAINLIEST‼️

Mathematics

1 answer:

sasho [114]3 years ago

6 0

Answer:

Hi how are you doing today Jasmine

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How could I write this out?

Crazy boy [7]

Answer:

1.6 divided by 8 is 0.2

Step-by-step explanation:

7 0

3 years ago

A central angle intercepts an arc on a circle equal in length to a diameter of the circle. find the measure in radians, or centr

Nitella [24]

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4 0

4 years ago

What does I cubed mean? I foreal need help

Fantom [35]

I=√-1
i^2=-1
i^3=-i
i^4=1

8 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

lubasha [3.4K]

First find a parameterization for the curve of intersection.

Given the equation of a cylinder, a natural choice for a parameterization would be one utilizing cylindrical coordinates. Here,

$16x^2+y^2=16\implies x^2+\left(\dfrac y4\right)^2=1$

which suggests we could use

$\begin{cases}x(t)=\cos t\\y(t)=4\sin t\\z(t)\end{cases}$

with $0\le t\le2\pi$ , and we get $z(t)$ from the equation of the plane,

$x+y+z=12\implies z(t)=12-x(t)-y(t)=12-\cos t-4\sin t$

Now use the arc length formula:

$\displaystyle\ell=\int_0^{2\pi}\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$

$\displaystyle\ell=\int_0^{2\pi}\sqrt{\sin^2t+16\cos^2t+(\sin t-4\cos t)^2}\,\mathrm dt$

$\displaystyle\ell=\sqrt2\int_0^{2\pi}\sqrt{\sin^2t-4\cos t\sin t+16\cos^2t}\,\mathrm dt\approx\boxed{24.0878}$

4 0

4 years ago

Find the area of the polygon shown. Enter the number into the box.

Maslowich

The required polygon whose area is to be calculated is attached below :

Answer:

16 unit²

Step-by-step explanation:

From the graph, the polygon is a triangle with height of 8 units and base of 4 units ;

Area of a triangle is given as :

Area = 1/2 * base * height

Area = 1/2 * 4 * 8

Area = 2 * 8

Area = 16 unit²

3 0

3 years ago