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Free_Kalibri [48]

2 years ago

11

Can anyone please help me with this RSM question? I have literally posted this like four times!

2 answers:

Ostrovityanka [42]2 years ago

5 0

Answer:

Angles in a triangle add up to 180.

ABG - x + 90 + ANGLE AGB = 180

Angles on a straight add up to 180.

CDE - 8x + ANGLE D + 3x = 180

Alterate angles - ATTACHMENT

ANGLE D = x

8x + x + 3x = 180

12x = 180

x = 180/12

<h2>x = 15</h2>

zlopas [31]2 years ago

5 0

Answer:

x = 15

Step-by-step explanation:

Line FD is perpendicular to line EB. Line AC is perpendicular to line EB. Lines that are perpendicular to the same line are parallel. That makes lines FD and AC parallel. Angles EDF and C are corresponding angles of parallel lines cut by a transversal, so they are congruent. That makes m<C = m<EDF = 3x.

The sum of the measures of the angles of a triangle is 180 degrees.

Look at triangle ACD.

m<A + m<C + m<ADC = 180

x + 3x + 8x = 180

12x = 180

x = 15

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H and J are both between G and K such that GH = JK and H is between G and J.

DIA [1.3K]

Answer:

32

Step-by-step explanation:

So the order of the points is: GHJK

GH = x+10 =JK

HJ=8

JK=2x-4

JK = x+10=2x-4

x+10=2x-4

10+4=2x-x

x=14

GH= 14+10 =24

GJ = GH +HJ = 24+ 8=32

6 0

2 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

2 years ago

5x+2=5x+2 has how many solutions?

tigry1 [53]

It has 1 solution i believe

8 0

2 years ago

paul can be choose to be paid 50 dollars for a job or he can be paid 12:50 per hour. under what circumstances should he choose t

umka21 [38]

12.50x4=50. If he works more than 4 hours he will earn more money from hourly.

3 0

3 years ago

Use a half-angle identity to find the exact value of sin pi/8

riadik2000 [5.3K]

Use a half-angle identity to find the exact value of sin pi/8

6 0

2 years ago

Read 2 more answers