Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Answer:
gmkyhmfnggnjggfbvmhfjxxjyyjyjhchhfxg
Step-by-step explanation:
Answer:
(0, 9 ) and (- 4, 1 )
Step-by-step explanation:
To determine which ordered pairs lie on the graph substitute the x- coordinate of the point into the right side of the equation and compare the value obtained with the y- coordinate
(- 20, - 49 )
2x + 9 = (2 × - 20) + 9 = - 40 + 9 = - 31 ≠ - 49
(1, 10 )
2x + 9 = (2 × 1) + 9 = 2 + 9 = 11 ≠ 10
(0, 9 )
2x + 9 = (2 × 0) + 9 = 0 + 9 = 9 ← point lies on graph
(- 4, 1 )
2x + 9 = (2 × - 4) + 9 = - 8 + 9 = 1 ← point lies on graph
(- 3, 40 )
2x + 9 = ( 2 × - 3) + 9 = - 6 + 9 = 3 ≠ 40
alligators:
x = total number of alligators
n = number of years
x=20x1.25^n
crocodiles:
y = total number of crocodiles
n = number of years
y=25+10n
Answer:
(8,-7)
Step-by-step explanation:
