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QveST [7]
2 years ago
12

Select all of the following expressions that are equivalent to 9 to the 1/2 power

Mathematics
1 answer:
daser333 [38]2 years ago
5 0

Step-by-step explanation:

x to the power of 1/2 means sqrt(x) (square root).

so, 9 to the power of 1/2 = sqrt(9) = 3.

therefore, we are looking for expressions that are also 3.

3 to the power of 1/2 = sqrt(3).

sqrt(3) × sqrt(3) = 3

this is correct

27 = 3×3×3

so, the cubic root would be 3 and correct, but the 6th root is incorrect.

27 to the power of 1/3 means the cubic root of 27, which is 3. but this is still multiplied by 3 to the power of 1/2 (sqrt(3)). so, the result is not 3 and therefore incorrect.

81 to the power of 1/2 = sqrt(81) = 9

9×9 = 81 and not 3. this is therefore incorrect.

729 to the power of 1/6 is the 6th root of 729, which is 3. this is therefore correct.

81 to the power of 1/3 means the cubic root of 81. but 81 is not a cubic number, and also multiplying this again with the cubic root of 81 is not 3. this is therefore incorrect.

81 to the power of 1/4 means the 4th root of 81. which is the square root of the square root.

the square root of 81 = 9. and the square root of 9 = 3.

3×3 = 9 and not 3. this is therefore incorrect.

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3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

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Answer:

YES ITS C

Step-by-step explanation:

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