Answer:
18 units
Step-by-step explanation:
So let's list out the sides.
for the first square let's just call them x
for the second square then they would be x+5 and x-3
So let's write out their areas we will cal the area of the first one z
x*x = z
(x+5)*(x-3) = z+21
since z = x^2 we can set up the second equation as a quadratic.
(x+5)*(x-3) = x^2 + 21
x^2 - 3x + 5x - 15 = x^2 + 21
But look, the x^2s cancel out
2x - 15 = 21
2x = 36
x = 18
Test it out and see if it fits the description, And if you don't understand anything just let me know so I can explain more.
Answer: a6=70
Step-by-step explanation:
we know that
In the Arithmetic Sequence the formula is:
an= a1 + d(n−1)
where
a1 is the first term
d is the common difference
n is the number of terms
in this problem
a1=5
a2=18
a3=31
a4=44
a5=57
so
d=a2-a1 or a3-a2 or a4-a3 or a5-a4
d=57-44----> 13
find a6
a6= a1 + d(n−1)
n=6
d=13
a1=5
a6=5+13*(6-1)----> a6=5+13*5----> a6=70
You would isolate the variable for ex
2x+3=9
2x=9-3
2x=6
x=3
Answer:
no
Step-by-step explanation:
2:4 is 1:2, 6:16 is not one half
Answer:
c
Step-by-step explanation:
