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tangare [24]
3 years ago
8

a store sells new DVDs for $12 each. used DVDs sell for $7 each. Joseph is buying two new DVDs and X used DVDs. write an equatio

n that can be used to find X, the total Joseph must pay in dollars
Mathematics
2 answers:
vagabundo [1.1K]3 years ago
7 0
Given that new DVDs are selling for $12 and used for $7, then Joseph is buying:
12·2 + 7<em>x </em>= 

earnstyle [38]3 years ago
7 0
Used DVDs = x
Total = t

t = 12(2) + 7x
t = 24 + 7x
t - 24 = 7x 
(t - 24) / (7) = x

If given the total, you can plug it in to variable t and then work the right side of the equation to isolate variable x and solve to find its value. 


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What is the diameter of a circle with a radius of 7 inches
In-s [12.5K]

Answer:

14

Step-by-step explanation:

the diameter is the radius multiplied by 2

7 0
3 years ago
What is the inverse of the function y = -8x + 15?
MrRa [10]

y = -8x + 15\\ 8x=-y+15\\ x=-\dfrac{y-15}{8}\\\\ y^{-1}=-\dfrac{x-15}{8}

6 0
3 years ago
Dan buys a car for £2200.
KatRina [158]

Answer:

The worth of the car after 6 years is £2,134.82

Step-by-step explanation:

The amount at which Dan buys the car, PV = £2200

The rate at which the car depreciates, r = -0.5%

The car's worth, 'FV', in 6 years is given as follows;

FV = PV \cdot \left ( 1 + \dfrac{r}{100} \right )^n

Where;

r = The depreciation rate (negative) = -0.5%

FV = The future value of the asset

PV = The present value pf the asset = £2200

n = The number of years (depreciating) = 6

By plugging in the values, we get;

FV = 2200 \times \left ( 1 + \dfrac{-0.5}{100} \right )^6 \approx 2,134.82

The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))

8 0
3 years ago
Help I’m stuck on this question I’ve been stuck on it for a while I can’t seem to figure it out please help for ten points
Naddika [18.5K]

Answer:

\frac{1}{25}

Step-by-step explanation:

I think what it is trying to say is that it wants the solution to multiplying all of those. The (...) simply means that it wants you to continue that pattern in what you are supposed to be multiplying, but stop at \frac{24}{25}.

That would mean you are technically supposed to be multiplying:

\frac{1}{2}  \frac{2}{3} \frac{3}{4} \frac{4}{5} \frac{5}{6} \frac{6}{7} \frac{7}{8} \frac{8}{9} \frac{9}{10} \frac{10}{11} \frac{11}{12} \frac{12}{13} \frac{13}{14} \frac{14}{15} \frac{15}{16} \frac{16}{17} \frac{17}{18} \frac{18}{19} \frac{19}{20} \frac{20}{21} \frac{21}{22} \frac{22}{23} \frac{23}{24} \frac{24}{25}

That is a lot and unfortunately, none of the individual fractions can be simplified within that. The final answer would be able to be simplified, though.

Multiplying the first four shown: \frac{1}{2}\frac{2}{3} \frac{3}{4} \frac{4}{5} you end up with \frac{24}{120}. Both the numerator (top) and the denominator (bottom) are divisible by 24. Dividing top and bottom would simplify this to \frac{1}{5}.

Now, let's take the next four.

\frac{5}{6}\frac{6}{7} \frac{7}{8} \frac{8}{9} allows you to end up with \frac{1680}{3024}. Both the numerator (top) and the denominator (bottom) are divisible by 336. You are left with \frac{5}{9}.

Now, let's take the next four.

\frac{9}{10}\frac{10}{11} \frac{11}{12} \frac{12}{13}. Multiplying these gives you \frac{11880}{17160}. Both the numerator (top) and the denominator (bottom) are divisible by 1320. You are left with \frac{9}{13}.

Now, let's take the next four.

\frac{13}{14}\frac{14}{15} \frac{15}{16} \frac{16}{17}. Multiplying these gives you \frac{43680}{57120}. Both the numerator (top) and the denominator (bottom) are divisible by 3360. You are left with \frac{13}{17}.

*<em> Although I would continue to say let's take the next four, there appears to be a pattern in the simplification. The numerators we have gotten have all been four less than their denominators, and each numerator has been four more than the last. I cannot be certain, but we only have two sets of four left. If this pattern continues, the simplifications of each should be \frac{17}{21} and \frac{21}{25}. I will continue on for argument's sake, anyways.</em>

The next four are \frac{17}{18}\frac{18}{19} \frac{19}{20} \frac{20}{21}. Multiplying these, you are left with \frac{116280}{143640}. Both the numerator (top) and the denominator (bottom) are divisible by 6840. We are left with\frac{17}{21}. This is the exact guess I had made when following the pattern, and so the next one is most likely going to be the other guess as well.

Our final answer will be \frac{1}{5}\frac{5}{9} \frac{9}{13} \frac{13}{17}\frac{17}{21} \frac{21}{25} all multiplied together. We end up with \frac{208845}{5221125}. Both the numerator (top) and denominator (bottom) are divisible by 208845.

Simplified, your final answer is:  \frac{1}{25}.

* <u>NOTE:</u> that another way to solve this would just be to multiply all numbers from 1-24 together and then 2-25, but you would end up with a very large number that would be just as time consuming to simplify. To get the GCF fast, I used a GCF calculator.

6 0
2 years ago
a boat builer wamts to make a modle of a schooner, a type of sailboatwith at least two masts. the schooner is 34 meters in lengt
BlackZzzverrR [31]
First you should set up fractions equal to each other to see the size ratio

8/34 = x/1.2

As to make comparable fractions. Then you would cross multiply in order to get
34x = 9.6
Divide both sides by 34 and you should get an answer of 0.28m for the model beam.
6 0
3 years ago
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