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Ede4ka [16]
3 years ago
12

Help me pls I give 15 points.

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
7 0

Answer:

B

Step-by-step explanation:

In order to eliminate the y-values you can make them equal. In this case, making them both -2.

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In the proportion 2:3 = 16:24 ,the product of the two middle values is __.
klio [65]

Answer:

48 and 48

Step-by-step explanation:

product means multiplication

two middle values are 3 and 16

3*16 = 48

two outside values are 2 and 24

2*24 = 48

4 0
3 years ago
Solve a^3 • (-a^2b)^4
Varvara68 [4.7K]

Answer:/?idk

Step-by-step explanation:


8 0
3 years ago
What is the surface area of the cylinder with height 7 cm and radius 5 cm? Round
nalin [4]

Answer:

376.991 cm²

Step-by-step explanation:

SA_{cylinder} = 2\pi r^{2}  + 2\pi rh

Surface Area = 2π(5²) + 2π(5)(7)

                      = 50π + 70π

                      = 120π

                      = 376.9911184... ≈ 376.991

<h2>Derive Surface Area of A Cylinder</h2>

If you take a look at a net of a cylinder, you can see it is composed of two circles(bases) and a rectangular strip with the length of the diameter of the circle

The formula for the area of a circle = πr², and since there are 2, it is 2πr²

The formula for circumference of a circle = 2πr, and since we are multiplying that by the height by the height of the cylinder, it is 2πrh

∴ 2πr² + 2πrh

5 0
3 years ago
Geometric mean. Find x, y, and z. Show work please.
Aleks [24]

Answer:

Step-by-step explanation:

i dont know the rest but the answer to x is 15 because the formula to that triangle is A^2+B^2=C^2

A=12

B=9

144(12^2) and 81 (9^2) add

225

find square root

15

z=15

4 0
3 years ago
In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
ladessa [460]

Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )

where n\left ( N\cup E\right )=Students either nose or ear Pierced

n\left ( N\cap E\right )=no of students having both nose and ear pierced

40=7+36-n\left ( N\cap E\right )

n\left ( N\cap E\right )=43-40=3

3 0
3 years ago
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