1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crazy boy [7]
3 years ago
11

The segments shown below could form a triangle. A. True B.false

Mathematics
2 answers:
Airida [17]3 years ago
6 0

Answer:

I don't no

Step-by-step explanation:

ok thanks for the

anyanavicka [17]3 years ago
5 0

Answer:

False

Step-by-step explanation:

Its false try using the app triangle calculator

You might be interested in
Find the values of x and y that maximize the objective function P=3x+2y for the graph. What is the maximum value?
AURORKA [14]

Answer:

(9, 0)

Step-by-step explanation:

Maximum or minimum value occurs at the Corner. The points given are (0, 8), (5, 4) and (9, 0).

Substitute (0, 8) in the objective function.

We get P = 3(0) + 2(8) = 16

Now for (x , y) = (5, 4)

P = 3(5) + 2(4) = 15 + 8 = 23

At (9, 0) we get P = 3(9) + 2(0) = 27.

Clearly, we have the maximum value at (9, 0).

And the maximum value is 27.

3 0
3 years ago
What’s the correct answer for this?
zalisa [80]

Answer:

AP = 14

Step-by-step explanation:

According to secant-secant theorem

(CP)(PD)=(BP)(AP)

7×12=6×AP

AP = 84/6

AP = 14

3 0
3 years ago
X+y+z=12<br> 6x-2y+z=16<br> 3x+4y+2z=28<br> What does x, y, and z equal?
lianna [129]

Answer:

x = 20/13 , y = 16/13 , z = 120/13

Step-by-step explanation:

Solve the following system:

{x + y + z = 12 | (equation 1)

6 x - 2 y + z = 16 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Swap equation 1 with equation 2:

{6 x - 2 y + z = 16 | (equation 1)

x + y + z = 12 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/6 × (equation 1) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+(4 y)/3 + (5 z)/6 = 28/3 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Multiply equation 2 by 6:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+5 y + (3 z)/2 = 20 | (equation 3)

Multiply equation 3 by 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+10 y + 3 z = 40 | (equation 3)

Swap equation 2 with equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+8 y + 5 z = 56 | (equation 3)

Subtract 4/5 × (equation 2) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+(13 z)/5 = 24 | (equation 3)

Multiply equation 3 by 5:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+13 z = 120 | (equation 3)

Divide equation 3 by 13:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y+0 z = 160/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 2 by 10:

{6 x - 2 y + z = 16 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Add 2 × (equation 2) to equation 1:

{6 x + 0 y+z = 240/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract equation 3 from equation 1:

{6 x+0 y+0 z = 120/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 1 by 6:

{x+0 y+0 z = 20/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Collect results:

Answer:  {x = 20/13 , y = 16/13 , z = 120/13

8 0
3 years ago
Multiply (6x+4y)(6x-4y)
MAXImum [283]
<h2><u><em>36x squared - 16y squared </em></u></h2>
6 0
3 years ago
Aaron was offered a job that paid a salary of \$57,000$57,000 in its first year. The salary was set to increase by 1% per year e
Jobisdone [24]

Answer:

The total amount received is: $1906650

Step-by-step explanation:

Given

a = \$57000 --- initial

b = 1\% --- rate

n = 29 --- time

Required

Determine the total amount at the end of 29 years

The given question is an illustration of geometric progression, and we are to solve for the sum of the first n terms

Where n = 29

r = 1 + b

r = 1 + 1\%

Express percentage as decimal

r = 1 + 0.01

r = 1.01

The required is the calculated using:

S_n = \frac{a(r^n - 1)}{r - 1}

So, we have:

S_n = \frac{57000 * (1.01^{29} - 1)}{1.01 - 1}

S_n = \frac{57000 * (1.3345- 1)}{0.01}

S_n = \frac{57000 * 0.3345}{0.01}

S_n = \frac{19066.5}{0.01}

S_n = 1906650

<em>The total amount received is: $1906650</em>

8 0
3 years ago
Other questions:
  • Please look at the picture down below
    15·1 answer
  • What equation is equal to 24x+(-12)+8
    15·2 answers
  • A stick of butter weighs a quarter pound.
    13·2 answers
  • Urgent plz no one helps me!!!!!!!!!!!!
    8·1 answer
  • Enter a digit in each box to complete the subtraction problem.
    13·1 answer
  • What is the measure of the angle at the tail end of the kite?
    7·1 answer
  • -60+x-23=70<br> Need help
    14·1 answer
  • Find the slope of each graph. Express the answer in simplest form. Please show graph​
    6·2 answers
  • Find the L.C.M of = <br>A) 12<br>B) 1/2<br>C) 7<br>D) 24<br>​
    11·1 answer
  • If I earn $15/hour and work for 20 hours/week, how much would I earn in one
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!