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mestny [16]
3 years ago
15

Please help me asap​

Mathematics
2 answers:
Ivenika [448]3 years ago
7 0

Answer:

the answer would be 3.

Step-by-step explanation:

5 times 3 is 15 plus 40 is 55. Hope this helps!!! Please let me know if i'm right!!!

Elenna [48]3 years ago
6 0

Answer:

Not sure what number sense is, but 3 is the answer.

Step-by-step explanation:

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What is an equation of the line that passes through the point (-3, 4) and is parallel
kompoz [17]

Answer:

y = 2/3x + 6

Step-by-step explanation:

If two lines are parallel, that means their slopes are the same.

Rewrite 2x - 3y = 15 to y = 2/3x - 5

The slope is 2/3, so the answer should have a slope of 2/3 as well.

The equation is now y = 2/3x + b

To find b, substitute (-3,4)

y = 2/3x + b

4 = 2/3(-3) + b

4 = -2 + b

6 = b

So the equation is y = 2/3x + 6

3 0
3 years ago
the lines below are parallel. if the slope of the green line is -3, what is the slope of the red line
strojnjashka [21]
The slope of the red line would also be -3 because the lines are parallel, and parallel lines have the same slope.
5 0
4 years ago
The number of dimes in Kiara's collection is 13 more than 5 times the
Delvig [45]

Answer:

The number of dimes in Kiara's collection is 13 more than 5 times the

number of quarters in her collection. Kiara has 78 dimes in her

collection.

<h3>3) 78 = 5C+13</h3>

is the right answer.

5 0
3 years ago
Wich one of the following items is an exmple of software?
saul85 [17]
A) Word-processing program is an example of a software
6 0
3 years ago
Read 2 more answers
A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em />cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

Step-by-step explanation:

Given

P\ (a,b)

r = \± \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

cos\theta is calculated as thus

cos\theta = \frac{a}{r}

Substitute r = \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}

cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0
3 years ago
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