It should be 40 ~
6*10=60
5*4=20
60-20=40
answer:
<h2>F2= 5kN</h2>
step by step explanation
<em>Note the second diameter was used as 50cm and not 500cm</em>
given
F1=800N
D1=20cm
A1=πD1^2/4
=3.142*20^2/4
=314.2cm^2
D2= 50cm
A2=πD2^2/4
=3.142*50^2/4
=1963.75cm^2
The pressure applied on the smaller relative to the bigger end is expressed as
F1/A1=F2/A2
substitute we have
800/314.2=F2/1963.75
cross multiply we have
F2=800*1963.75/314.2
F2=1571000/314.2
F2=5000N
F2=5kN
The larger Force is 5kN
Answer:
Step-by-step explanation:
-This is a linear relationship problem modeled as:
where:
is the quantity at variable x
is the slope
is the constant of increment or decrement.
is the variation variable.
Given the constant 40, and 12 pages per day as the rate of change we substitute our variables in the form of the formula above as:
