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Tems11 [23]
3 years ago
15

-4/3(3q-10) simplified

Mathematics
2 answers:
monitta3 years ago
4 0

Answer:

Answer in the photo

Step-by-step explanation:

Just simplify the expression

Rasek [7]3 years ago
4 0

Answer:

its -4q+ 40/3

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ad-work [718]
If you divide 21/49 by 7 you get 3/7
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3 years ago
After school, Hugo helps out at a bunny shelter called Hoppy's Home. He cleans cages and feeds all 8 bunnies at the shelter. In
amm1812

Answer:

25.3

1_ draw a triangle

the shortest side is a which will be 8(bunnies)

diagonal will be c ( what you need to find )

the last side will be b.

so the equation is a2+b2=c2 ( 2=squared)

that means..... 8x8+24x24=c

8x8=64

24x24=576

then add

576+64=640

the find square root

√640=25.2982212813

simplify to 25.3

you know your answer is correct because c is always the biggest side

5 0
3 years ago
Which word in the sentence below is an interrogative pronoun?
Schach [20]
Us would be the answer to this question
4 0
3 years ago
Just need the answers to see if im right lol
denis-greek [22]

Answer:

what is the question ? Volume or surface area???

6 0
3 years ago
Find the point on the parabola y^2 = 4x that is closest to the point (2, 8).
guapka [62]

Answer:

(4, 4)

Step-by-step explanation:

There are a couple of ways to go at this:

  1. Write an expression for the distance from a point on the parabola to the given point, then differentiate that and set the derivative to zero.
  2. Find the equation of a normal line to the parabola that goes through the given point.

1. The distance formula tells us for some point (x, y) on the parabola, the distance d satisfies ...

... d² = (x -2)² +(y -8)² . . . . . . . the y in this equation is a function of x

Differentiating with respect to x and setting dd/dx=0, we have ...

... 2d(dd/dx) = 0 = 2(x -2) +2(y -8)(dy/dx)

We can factor 2 from this to get

... 0 = x -2 +(y -8)(dy/dx)

Differentiating the parabola's equation, we find ...

... 2y(dy/dx) = 4

... dy/dx = 2/y

Substituting for x (=y²/4) and dy/dx into our derivative equation above, we get

... 0 = y²/4 -2 +(y -8)(2/y) = y²/4 -16/y

... 64 = y³ . . . . . . multiply by 4y, add 64

... 4 = y . . . . . . . . cube root

... y²/4 = 16/4 = x = 4

_____

2. The derivative above tells us the slope at point (x, y) on the parabola is ...

... dy/dx = 2/y

Then the slope of the normal line at that point is ...

... -1/(dy/dx) = -y/2

The normal line through the point (2, 8) will have equation (in point-slope form) ...

... y - 8 = (-y/2)(x -2)

Substituting for x using the equation of the parabola, we get

... y - 8 = (-y/2)(y²/4 -2)

Multiplying by 8 gives ...

... 8y -64 = -y³ +8y

... y³ = 64 . . . . subtract 8y, multiply by -1

... y = 4 . . . . . . cube root

... x = y²/4 = 4

The point on the parabola that is closest to the point (2, 8) is (4, 4).

4 0
3 years ago
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