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3 years ago

Complete the following equivalent fraction: = 9 15 36 18 0 000 20 12

Mathematics

1 answer:

postnew [5]3 years ago

5 0

Answer:

9 Hawthorne Wyndham Garden Ann Arbor Ann Arbor Euro Ponte Vedra Beach Terrell give me the phone number give me a number good night Emily and Abra midnight give me a number hey baby give me call Big Baby

Step-by-step explanation:

give me a number baby you're not baby give me my pictures Cannonball picture

You might be interested in

Write the following in expanded form then in word form . number 355,645

valkas [14]

Answer:

300000+50000+5000+600+40+5

word form:- three lakh fifty five thousand six hundred forty five.

3 0

3 years ago

The question is below

Elanso [62]

9514 1404 393

Answer:

162°

Step-by-step explanation:

The measure of inscribed angle ADC is half the measure of the intercepted arc AC. That arc has a measure that is the same as the central angle it subtends, angle ABC.

So, central angle ABC is twice the measure of inscribed angle ADC:

m∠ABC = 2·81° = 162°

6 0

2 years ago

AB = 3 + x

ICE Princess25 [194]

The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.

Step-by-step explanation:

ABCD is a quadrilateral with their opposite sides are congruent (equal).

The both pairs of opposite sides are given as AB = 3 + x , DC = 4x , AD = y + 1 , BC = 2y.

AB and DC are opposite sides and have same measure of length.
AD and BC are opposite sides and have same measure of length.

To find the length of AB and DC :

AB = DC

3 + x = 4x

Keep x terms on one side and constant on other side.

3 = 4x - x

3 = 3x

x = 1

Substiute x=1 in AB and DC,

AB = 3+1 = 4

DC = 4(1) = 4

To find the length of AD and BC :

AD = BC

y + 1 = 2y

Keep y terms on one side and constant on other side.

2y-y = 1

y = 1

Substiute y=1 in AD and BC,

AD = 1+1 = 2

BC = 2(1) = 2

Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.

6 0

3 years ago

1 + tanx / 1 + cotx =2

Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer: x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0

3 years ago

4+(−1 2/3) i don't get how to this cuz there aren't two fractions, just one.

kenny6666 [7]

Answer:

2 1/3

Step-by-step explanation:

4 + ( -1 2/3)

= 4 - 1 2/3

= 4 - 5/3

= 12/2 - 5/3

= 7/3

= 2 1/3

5 0

2 years ago