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FinnZ [79.3K]
3 years ago
5

2/3x=4 what does x equal?

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

0=6

Step-by-step explanation:

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In the sequence 0, 1, 1, 3, 6, 9, 27, ..., the first term is 0. Subsequent terms are produced by alternately adding and multiply
salantis [7]

Answer:

645

Step-by-step explanation:

Let's first try and write our series up to 125 before we know the next number.

Well continue from the given series.

0, 1, 1, 3, 6, 9, 27

The next number= 27+4= 31 , then 31 *4 = 124

The next after 124 = 124+5= 129, then 129*5 = 645

So actually the question was supposed to be the term greater than 124 because 125 does not exist in the series.

The number is 645

5 0
4 years ago
The sum of three numbers is -44.84. One of the numbers is 26.6. The other two numbers are equal to each other. What is the value
docker41 [41]
A+b+c=-44.84

a=26.6
b=c

26.6+b+b=-44.84

2b=-44.84-26.6

b=-35.72


So, a=26.6, b=-35.72, c=-35.72
8 0
3 years ago
A company packages its milk powder in cylindrical
Roman55 [17]

Answer:

704 cm²

Step-by-step explanation:

The circumference of the cylindrical container is given by 2πr.

Now, r = radius of the base  

If the diameter of the base is 14 cm then the radius will be 7 cm.

So, the circumference = \frac{2 \times 22 \times 7}{7} =44 cm.

Now, the label around the surface of the container placed 2 cm from top and bottom.

Therefore, the width of the label is (20 - 2 - 2) = 16 cm and the length is 44 cm.

Hence, the area of each label is (44 × 16) = 704 cm² (Answer)

3 0
4 years ago
Given that <2=<6.
Misha Larkins [42]

Answer: B . Converse of the alternate exterior angle theorem.

5 0
4 years ago
Can a quadratic polynomial equation with real coefficients have one real solution and one complex solution? If so,
Anastasy [175]

Answer:

No

Step-by-step explanation:

We have to find that a quadratic polynomial equation with real coefficient can have one real solution and one complex solution.

quadratic equation is given by

ax^2+bx+c=0

It can be written as  the product of linear factors

ax^2+bx+c=a(x-r_1)(x-r_2)

Where r_1,r_2 are solutions of the given  polynomial equation.

No , a quadratic polynomial equation can not  have one real solution and one complex solution because complex root are always in paired not a single.

A quadratic equation have two roots only.

If a quadratic equation have complex root then the equation have both complex root .

If  a equation have real root then it have both real.

Therefore, a quadratic equation can not have one real and one compelx solution.

5 0
3 years ago
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