Isolate the variable by dividing each side by factors that don't contain the variable.
h = −8
Answer:
10 points
Step-by-step explanation:
Points scored in each of the first 3 quarter = x
Total points scored in the first 3 quarter = x + x + x
= 3x
Points scored in the fourth quarter = 14
Total points scored = 44 point
Total points scored = Total points scored in the first 3 quarter + Points scored in the fourth quarter
44 = 3x + 14
Subtract 14 from both sides
44 = 3x + 14
44 - 14 = 3x + 14 - 14
30 = 3x
Divide both sides by 3
x = 30/3
= 10
x = 10 points
Points scored in each of the first 3 quarter = x = 10 points
The school football team scored 10 points points in the first quarter
Answer:
y = -6
Step-by-step explanation:
y=acos(bx+c)+d
d = -6 .. vertical shift
midline: y = -6
Assuming that both triangles are an exact copy of one another, it is safe to assume that 3y-7 is equal to 41. Set up an equation
3y-7=41
Add 7 to both sides
3y=48
Divide both sides by 3
y=16
Now to find PN.
Based on what we know, we can assume that MP = PN. Let's make some equations!
MP = 17x-8 PN = 11x+4
17x-8 = 11x+4
Subtract 11x from both sides
6x-8 = 4
Add 8 to both sides
6x = 12
Divide by 2
x=2
Substitute 2 in for x in the equation for PN
11(2)+4
Multiply 11 by 2
22+4 = 26
PN = 26
A. The figure is a triangular pyramid. You can findits surface area by adding up the area of the three faces of the triangle and the area of the base. A derived formula also is used where the SA is equal to 12 times the perimeter of base times the slant height, added to that is the area of the base. The area of the square base is s^2. Its perimeter is 4s.
SA of Pyramid = 12*P*l + s^2
SA of Pyramid = 12*4s*l + 16^2
SA of Pyramid = 12*4(16)*(17) + (16)^2
SA of Pyramid = 11,008 square inches
b.) The formula for the SA of a cone is:
SA of cone = πr[r+√(h^2+r^2)]
SA of cone = π(3)[(3+√(8^2+3^2)]
SA of cone = 108.8 square inches
