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Lynna [10]
3 years ago
6

The teacher does not have to spend all $36. Write an inequality relating 36 and 9 (7 - x) representing this situation. (Copy/pas

te as needed: ≤ ﹤ ≥ ﹥)
Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

<h3>9(7-x) < 36</h3>

Step-by-step explanation:

From the question, we are to relate the amount the teacher spent to the expression 9(7-x).

Since the teacher does not have to spend all the $36, this means that he spent amount less than $36 but not equal to $36. Hence the best inequality sign that relates both expression is a less than sign (<) as shown;

9(7-x) < 36

hence the required inequality is 9(7-x) < 36

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Solve -4 &lt; 3x+2&lt;5.
denis-greek [22]

The answer choice which represents the solution to the inequality as given in the task content is; x>-2 or x≤ 1.

<h3>What is the solution of the give complex inequality?</h3>

On this note, it follows that the inequalities can be solved individually as follows;

-4 < 3x +2

-6 < 3x

x > -2

Also, 3x +2 ≤ 5

3x ≤ 3

x ≤ 1.

Ultimately, the correct answer choice is; Choice C; x>-2 or x≤ 1.

Read more on complex inequality;

brainly.com/question/24761100

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5 0
1 year ago
Simplify 3^-3<br> Show work
dmitriy555 [2]

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5 0
3 years ago
The ratio of pencils to erasers is 4:1 if there are 20 pencils how many erasers are there? Kerion has a beaded necklace business
Misha Larkins [42]

Answer:

we express the ratio of pencil to eraser and multiply it by the number of the number of pencils and erasers. 4/5 * x=20 , so x=25, then it implies that there are 5 erasers.

7 0
4 years ago
Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the
iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are \frac{10\sqrt{2} }{3}

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C  =  -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = \frac{10\sqrt{2} }{3}

From B = \frac{10\sqrt{2} }{3}

From C = \frac{10\sqrt{2} }{3}

7 0
3 years ago
Using the problem below, solve and explain how you got the solution to the system of equation.
Paul [167]

Answer:

(5, -3)

y= -3

x= 5

Step-by-step explanation:

-x-2y=1

x+y=2

solve the equation

-x-2y=1

x=2-y

substitute the value of x into an equation

-(2-y)-2y=1

remove parenthesis

-2-y-2y=1

subtract y to 2y

-2-y=1

add 2 from both sides

-y=3

divide both sides by -y

y= -3

substitute the value of y into an equation

x=2-(-3)

remove parenthesis

x=2+3

add 2 to 3

x=5

----------

(5,-3)

----------

7 0
3 years ago
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