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EleoNora [17]
3 years ago
11

Why is surface area measured in square units?

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

Answer: I think it's because most things were made as square units.

Step-by-step explanation:

denis23 [38]3 years ago
7 0
When a three dimensional object is folded flat, its area is calculated, and then it is no longer has volume, only length and bredth. Volume has cubic units.
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What is the simplified version of −(−3)2−−−−−−√?
erastovalidia [21]
6+1ty is the best thing to do with this
5 0
2 years ago
3a <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3a%20%2B%20a%20%7B%7D%5E%7B2%7D%20%7D%7Ba%7D%20" id="TexFormula1" title="
egoroff_w [7]

Answer:

(3+a)

Step-by-step explanation:

3a + a^2

-------------

a

Factor out an a in the numerator

a(3+a)

-------------

a

Cancel like terms

(3+a)

6 0
2 years ago
Read 2 more answers
Which ordered pair is a solution to this equation?
hjlf
The answer to this is (11, 1).
4 0
3 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
A store uses the expression -2p+ 50 to model the number of backpacks it sells per day, where the price, p, can be anywhere
Ivan

Answer:

B: $12.00 per backpack gives the maximum revenue; the maximum revenue is $312.00.

Step-by-step explanation:

3 0
3 years ago
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