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Natasha_Volkova [10]

3 years ago

7

How much is two thousand three hundred and five-tenths, plus one hundred twenty-five and one-hundredth, plus five thousand ten a

nd fifteen-hundredths?
A. 7,435.21
B. 7,435.66
C. 7,485.25
D. 7,590.1

2 answers:

mrs_skeptik [129]3 years ago

7 0

The answer is B.

Hope that helps, if you need any more help, just ask : )

ArbitrLikvidat [17]3 years ago

5 0

The answer is B 7,453.66

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Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

4 years ago

Pls help this is due soon check 2 that apply

dem82 [27]

Answer:

I am pretty sure it is option a and c

Sorry if i am wrong

3 0

3 years ago

Can you please help me I pay you £50

Ivahew [28]

(4,-2) (6,-2) (4,1) are co ordinates for the triangle after the movement

7 0

2 years ago

Solve the following system of equations. Express your answer as an ordered pair in the format (a,b) with no spaces between the n

Westkost [7]

The answer is 0 because 2+5 is 7 and then 5-2 is 7

6 0

4 years ago

yarga [219]

Answer:

The second term in the sequence is -9

Step-by-step explanation:

Given the nth term of a sequence to be a(n) = a(n-1)+4 where n is the number of terms of the sequence

If a(1) = -13... (1)

The second term of the sequence is generated for n= 2:

a(2) = a(2-1)+4

a(2) = a(1)+4... (2)

Substituting equation 1 into 2

a(2) = -13+4

a(2) = -9

The second term in the sequence is -8

6 0

3 years ago