Question

An article measured speeds of vehicles on several roads in the state of Kansas. On South Cedar Niles, 73 vehicles were observed, and 45 of them were exceeding the speed limit. Can you conclude that more than 60% of the vehicles on South Cedar Niles exceed the speed limit

Answer 1

Answer:

The $p-$ value is $0.2996$.

Step-by-step explanation:

This is a right-tailed test.

The null and alternative hypothesis is

$H_0:p=0.60\\H_a:p>0.60$

Point estimate $=$ sample proportion$=\hat{P}=x/n=0.630$

Test statistics

$z=\left(\hat{p}-p_{0}\right) / \sqrt{p}_{0^{*}}\left(1-p_{0)} / n\right. \\ =(0.630-0.60) / \sqrt{(0.60 * 0.40) / 73} \\ =0.526 \\P-value =P(Z>z) \\ =0.2996 \\The \mathrm{P} -value is 0.2996$