Answer:
77392>67993
Step-by-step explanation:
[ Answer ]
<u><em>1380</em></u>
[ Explanation ]
57 1/2 * (72 / 3)
72 / 3 = 24
57 1/2 * 24
Turn 57 1/2 into improper fraction:
115 / 2
115/2 * 24/1
Multiply across:
115 * 24
2 * 1
= 2760 / 2
= 1380
<u><em>> Eclipsed <</em></u>
The sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.
Step-by-step explanation:
First Term (a) = 4
Common difference (d) = 3
The number of term (n) = 20
The sum of an Arithmetic series of (n) number of terms, with first term (a) and the common difference (d) is equal to
Sum = (n/2) * ( 2 * a + (n -1) * d)
So putting the values of a,d, n
Sum = ( 20/2) * ( 2 * 4 + (20 -1) *3 )
Sum = (10) * ( 8 + 19 * 3)
Sum = 10 * ( 8 + 57)
Sum = 10 * 65 = 650
Hence the sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.
