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3 years ago

1. why is manufacturing considered the biggest contributor to progress

Computers and Technology

1 answer:

34kurt3 years ago

3 0

Answer:

A vibrant manufacturing base leads to more research and development, innovation, productivity, exports, and middle-class jobs. Manufacturing helps raise living standards more than any other sector. Manufacturing generates more economic activity than other sectors.

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Ternary operators of computer<br><br>please explain.

Nitella [24]

Answer:

It's a compact way of doing an if-else statement.

General Format is

<<em>condition</em>> ? <if condition is true> : <else>;

Example:

I could rewrite:

if(a==1) temp = 1;

else temp = 999;

temp = (a==1) ? 1 : 999;

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3 years ago

Can someone give me the code for the edhesive 3.7 code practice for python? Thanks.

belka [17]

Answer:

Its me I think u might be able to know :)

Explanation:

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3 years ago

Anchor hyperlink to position the cursor to the section called sisters? i need a code pls

enot [183]

use an anchor tag(<a>This is an anchor tag</a>) and use the href attribute and set it's destination to the section element who's id or class is "sisters".

Example:

<a href="#Sisters">Click Here!</a>

then you can add this somewhere on the document.

<section id="Sisters">Hello World!</section>

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3 years ago

You need to fax a portion of a map from a large hard-cover atlas to a client from an internal fax-modem. To fax the map, the bes

Kay [80]

The fax modem is used to send and receive fax messages by only having phone line (fax machine is not required). The scanned documents should be saved as digital file (image or PDF format) in order to be sent. So, in order to send a portion of a map you should first convert the map into digital file and than simply send it through the fax modem. The best way to convert it to a digital file is to use an optical character recognition (OCR).

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3 years ago

Write a program that converts a number entered in Roman numerals to decimal. your program should consist of a class, say, Roman.

arlik [135]

Answer:

The code is given below in Java with appropriate comments

Explanation:

import java.util.*;

public class RomantoDecimal {

public static void main(String[] args)

{

Scanner SC = new Scanner(System.in);

RomantoDecimal r = new RomantoDecimal();

System.out.println("Enter a Roman number :");

// INPUT A ROMAN NUMBER

String rNum = SC.next();

// CALL convertToDecimal FOR CONVERSION OF ROMAN TO DECIMAL

r.convertToDecimal(rNum);

}

// M=1000, D=500, C=100, L=50, X=10, V=5, I=1

public void convertToDecimal(String roamNo)

{

int number = 0;

// TEACK EACH DIGIT IN THE GIVEN NUMBER IN REVERSE ORDER

for (int i = roamNo.length() - 1; i >= 0; i--)

{

// FIND OUT WHETHER IT IS 'M' OR NOT

if (roamNo.charAt(i) == 'M')

{

if (i != 0)

{ // CHECK WHETHER THERE IS C BEFORE M

if (roamNo.charAt(i - 1) == 'C')

{

number = number + 900;

i--;

continue;

}

number = number + 1000;

}

// FIND OUT WHETHER IT IS 'D' OR NOT

else if (roamNo.charAt(i) == 'D')

{

if (i != 0)

{

// CHECK WHETHER THERE IS C BEFORE D

if (roamNo.charAt(i - 1) == 'C')

{

number = number + 400;

i--;

continue;

}

number = number + 500;

}

// FIND OUT WHETHER IT IS 'C' OR NOT

else if (roamNo.charAt(i) == 'C')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'X')

{

number = number + 90;

i--;

continue;

}

number = number + 100;

}

else if (roamNo.charAt(i) == 'L')

{

if (i != 0)

{

if (roamNo.charAt(i) == 'X')

{

number = number + 40;

i--;

continue;

}

number = number + 50;

}

// FIND OUT WHETHER IT IS 'X' OR NOT

else if (roamNo.charAt(i) == 'X')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'I')

{

number = number + 9;

i--;

continue;

}

number = number + 10;

}

// FIND OUT WHETHER IT IS 'V' OR NOT

else if (roamNo.charAt(i) == 'V')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'I')

{

number = number + 4;

i--;

continue;

}

number = number + 5;

}

else // FIND OUT WHETHER IT IS 'I' OR NOT

{

number = number + 1;

}

}// end for loop

System.out.println("Roman number: " + roamNo + "\nIts Decimal Equivalent: " + number);

}

3 0

3 years ago