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Afina-wow [57]
3 years ago
14

Sonia rolls a six-sided number cube 12 times and records if she rolls a 2. What is the number of trials for this binomial experi

ment?
A)2
B)6
C)12
D)18
Mathematics
1 answer:
loris [4]3 years ago
3 0
Answer: option C) 12

The number of trials is the number of times that she performs the experiment, i.e. the number of times she rolles the cube..
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What is 100/7 divided by 4 1/3 simplified if you answer thank you and happy holidays
SVETLANKA909090 [29]

Answer: 300/91

Step-by-step explanation:

1. Convert 4 1/3 to an improper fraction

13/3

2. Divide, using the keep, change, flip method to divide fractions

- Keep the first fraction the same (100/7)

- Change the division sign to a multiplication sign

- Flip the second fraction (13/3 -> 3/13)

3. Plug-in and evaluate

100/7 * 3/13

300/91

If you are looking for the solution as a mixed number, it is 3 27/91

4. Simplify, if applicable. This fraction cannot be simplified any further.

7 0
3 years ago
Hi guys<br>I need 3 minus and plus operations with answer thx!​
nata0808 [166]

1999+1001=3000 1091+1009=3000 2000+1000=3000

3000-1001=1999 3000-1009=1091 3000-2000=1000

8 0
2 years ago
Graph the image of the figure after a dilation with a scale factor of ½ centered at (4, 8).
Anastasy [175]

Answer:

A(4.5 , 7) B(6.5 , 7) C(6.5 , 4) D(2 , 4)

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
If y is 15 times x, which equation shows the relationship between x and y?
zhannawk [14.2K]
Is= equals sign
times= multiplication


So y equals 15 times x

y= 15 * x
y= 15x


ANSWER: y= 15x (bottom choice)

Hope this helps! :)
4 0
3 years ago
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
3 years ago
Read 2 more answers
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