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Elenna [48]
2 years ago
6

A large chess tourname begins with 256 players. After each round, r, half of the players remain

Mathematics
1 answer:
ivolga24 [154]2 years ago
6 0
Is there more to the question?
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A store sold $115.50 worth of coffee mugs. how many mugs did they sell? at3.50 per mug
Anna007 [38]
Total÷price each=amount sold
$115.50÷$3.50=33
The store sold 33 mugs
4 0
3 years ago
Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Rasek [7]

Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9842

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

7 0
3 years ago
Please help!!!<br> What is the area of the trapezoid?
olga nikolaevna [1]
330m^2 is the answer
6 0
2 years ago
Stephen record the growth of a plant over 10 weeks for his science project he made a graph that shows how much the plant group e
vazorg [7]

Answer:

y= 6/5x + 2

If you substitute the points (5,8) you get:

8 = 6/5 × 5 + 2

8 = 6 + 2

Step-by-step explanation:

5 0
3 years ago
Which of the following values has 4 significant figures?
Vlad1618 [11]

Answer:

А. 13.07

Step-by-step explanation:

Significant figures are the number of digit from a number that have meanings. The higher the significant figures of a number, the higher its accuracy will be.  The only non-zero number will be count as significant figures unless the zero is between two non-zero numbers like 13.07, the zero placed between 3 and 7. Some number also doesn't count as significant figures like the leading zero.

All other option just shows 3 significant numbers, so the answer is 13.07

6 0
3 years ago
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