Answer:
PQO and OQP
Step-by-step explanation:
PQO: lines OQ and PQ make the angle.
OQP: Not really sure why it asks for two names. You can probably just flip PQO to OQP and that might work. N is not part of the angle so you can't have an answer with that letter.
Answer:
Step-by-step explanation:
Let x be the track straights lengths
Let y be the track ends diameter and the other rectangle side lengths.
1800 = 2x + πy
y = (1800 - 2x) / π
A = xy
A = x((1800 - 2x) / π
A = (1/π)(1800x - 2x²)
dA/dx = (1/π)(1800 - 4x)
0 = (1/π)(1800 - 4x)
0 = 1800 - 4x
4x = 1800
x = 450 m
y = (1800 - 2(450)) / π
y = 900/π or approximately 286.5 m
The trapezoid formula is 1/2 (base 1+ base 2) x height. So if you work backwards you should be able to find the height. Could you give the base measurements?
Basically add the two negative number so -13 + -123 would be -136
7/8
8 times 7= 56
So the answer is 49/56 because to get the 8 to be a 56 we multiplied by 7 and whatever you do to the top you have to do to the bottom.
hope i helped :)