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Angelina_Jolie [31]
3 years ago
5

The volume of a square pyramid is given by the formula, V = 13hx2, where h is the height of the pyramid and x is the length of o

ne side of the base. If a pyramid has a height of 15 ft and a volume of 2,880 ft3, what is the length of one side of the base
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer: 24ft

Step-by-step explanation:

The exercise gives you the following formula:

Where "h" is the height of the square pyramid and "x" is the length of one side of the base.

According to the data given, you know that:

Therefore, you can subsitute these values into the formula:

Now, you need to solve for the "x" to calculate the length of one side of the square base of that pyramid.

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Add five thousand, three hundred and twelve thousandths to the product of one and thirty six hundredths and 15
MAVERICK [17]
First find the product of 1.36 and 15

1.36×15=20.4

5,300.012+20.4= 5,320.412

hope this is what you are looking for
7 0
3 years ago
What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
Help me with these problems (show work) thanks ❤️❤️
yanalaym [24]

Answer:

#1. 12x9x5+= 426

#2. 6x14.8= 784.14

#3. 6x6x8x8= 143.11

Step-by-step explanation:

Hoped that helped!

6 0
3 years ago
What is the prime factorization of 325
Tasya [4]
The Prime Factorization of 325
Answer : 5^2 • 13
hope this helps!!!
8 0
3 years ago
Sandra bought a tube of toothpaste for $1.89, shampoo for $3.19 and a jar of peanuts for $2.29 from the local supermarket. Using
uranmaximum [27]
To find the total cost, you need to add these numbers together

1.89 + 3.19 + 2.29 = 7.37
you get 7.37 as your answer, but you need to round this to the nearest whole number.

rounding 7.37 will make it 7.

the total cost is about $7
5 0
4 years ago
Read 2 more answers
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