Answer:
Range
The set of output values is called the range of the function.
Answer:
Here it is solved for rate:
log(1 + rate) = {log(total) -log(Principal)} ÷ Years
Let's work through your example:
log(1 + rate) = {log(6,680) -log(5,000)} / 6
log(1 + rate) = (3.8247764625 -3.6989700043) / 6
log(1 + rate) = 0.020967743
If we raise 10 to the 0.020967743 power
10^0.020967743 it produces 1 plus the rate
1 plus the rate = 10^0.020967743 = 1.0494644773
There fore the rate = .0494644773 which equals
4.94644773 per cent
Source: https://www.1728.org/compint2.htm
Step-by-step explanation:
Answer:
The discount was approximately 48%.
Step-by-step explanation:
The general forumla to calculate percent change (increase or decrease) is:
x 100
In this case, the original price was $28.00, but the new price (after discount) was $14.60. Putting these values into the formula:
x 100 = 48%.
Answer:
The variable y is eliminated.
Step-by-step explanation:
To add a system of equations, we add the common terms. x with x, y with y and values with values.
In this question:
5x + 6y = 32
5x – 6y = 8
Adding:
5x + 5x + 6y - 6y = 32 + 8
10x = 40
So the variable y is eliminated.
