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8_murik_8 [283]
3 years ago
11

What is -6ab^3 over 5a times 10b over -24ab^2

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0
The answer is: b²/2a
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Use the partial product stratagy to solve 429×35?
Korolek [52]
16731 should be the answer
6 0
3 years ago
Segment DE has endpoints at D(2, - 8) and E(-4, 4) . If it is dilated about the origin by a factor of 4, which of the following
VLD [36.1K]

Answer:

answer 2)  24\sqrt{5}

Step-by-step explanation:

after the dilation pt D is (8,-32)

after the dilation pt E is (-16,16)

if you use the distance formula for these two points you get \sqrt{2880} which simplifies to 24\sqrt{5}

3 0
3 years ago
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
Erin bought a $205 smart phone, but her total was $217.30. What percent sales tax did she pay?
andrey2020 [161]

Answer:

6.00 %

Step-by-step explanation:

205.00 × 0.060= 12.3

205.00 + 12.3= $217.30

6 0
2 years ago
Approximately how many kcal are contained in 3 ounces of 80-proof rum?
Mekhanik [1.2K]
3 ounces of 80-proof rum approximately contains 200,000 cal.

Now, we need to convert the cal into kcal. We know that:
1 cal = 1000 kcal
Therefore,
200,000 cal = 200 kcal
4 0
3 years ago
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