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3 years ago

What is -6ab^3 over 5a times 10b over -24ab^2

Mathematics

1 answer:

serious [3.7K]3 years ago

4 0

The answer is: b²/2a

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Ryan earns x dollars every seven days. Write an expression for how much Ryan earns in one day. Ryan’s spouse Lee is paid twice a

Travka [436]

Answer:

Step-by-step explanation:

R=x/7 let's say R is what Ryan earned, and so he earns x dollars every seven days

L=2(R)

L=2(x/7)Let's say L is what Lee earned, she earned twice as much as Ryan so 2(x/7)

Total=2(x/7)+x/7

Total=3(x/7) the total earnings is the sum of x/7 and 2x/7 is 3x/7

4 0

3 years ago

1.5 g = __?__ kg<br><br> 3 1-4 qt =__?__ pt<br><br> Help Is Appreciated!!!

zysi [14]

The first one is 0.0015

6 0

3 years ago

Suppose a line parallel to side BC of ABC intersects sides AB and AC at points X and Y, respectively. Find the length of AC if A

elena-s [515]

Answer: AC=3.5

Solve proportionally:3 over 4 equals 1.5 over x.

3x= 6

6/3=2

X=2

2+1.5=3.5

6 0

3 years ago

Read 2 more answers

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

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3 years ago

Find the square root of 784 using prime factorization.

WINSTONCH [101]

Answer:

first check the smallest number that divide 784

i.e 2

784/2 = 392/2= 196/2 =98/2 =49/7=7

we get

748= 2*2*2*2*7*7

for square root take one out of 2 same number

square root of 784= 2*2*7 = 28

7 0

3 years ago

Read 2 more answers