Answer:
center:
(-0.25, 5)
foci :
(-0.25, 0.158771) | (-0.25, 9.84123)
vertices :
(-0.25, -0.59017) | (-0.25, 10.5902)
wolframramalpha

2) 5.625 mg will be left
Explanation:
1) Half-life = 17.5 days
initial amount of Arsenic-74 = 90 mg
To get the equation, we will use the equation of half-life:


2) we need to find the remaining amount of Arsenic-74 after 70 days
t = 70

So after 70 days, 5.625 mg will be left
Answer:
x = 8
y = 16
Step-by-step explanation:
8 + 8 = 16
y = 16
Answer:
x+6 / 4x-5
Step-by-step explanation: